A uniform rod of density is placed in a wide tank containing a liquid . The depth of liquid in the tank is half the length of the rod. The rod is in equilibrium, with its lower end resting on the bottom of the tank. In this position, the rod makes an angle with the horizontal. Then is equal to |
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a) |
b) |
c) |
d) |

A uniform rod of density is placed in a wide tank containing a liquid . The depth of liquid in the tank is half the length of the rod. The rod is in equilibrium, with its lower end resting on the bottom of the tank. In this position, the rod makes an angle with the horizontal. Then is equal to |
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a) |
b) |
c) |
d) |

1 Answer

127 votes

**(a)**

Let = area of cross-section of the rod

Weight of the rod acting vertically downwards at

Upthrust of liquid on rod , acting upwards through the mid-point of

For rotational equilibrium of rod net torque about point should be zero. So

Or

127 votes

127