Let C1 and C2 be the centres of the circles x2+y2−2x−2y−2 = 0 and x2+y2−6x−6y+14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of quadrilateral PC1QC2 is
a.
8
b.
6
c.
9
d.
4
a.
8
b.
6
c.
9
d.
4
Question ID - 57196 | SaraNextGen Top Answer Let C1 and C2 be the centres of the circles x2+y2−2x−2y−2 = 0 and x2+y2−6x−6y+14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of quadrilateral PC1QC2 is
a.
8
b.
6
c.
9
d.
4
Let C1 and C2 be the centres of the circles x2+y2−2x−2y−2 = 0 and x2+y2−6x−6y+14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of quadrilateral PC1QC2 is
|
a. |
8 |
b. |
6 |
|
c. |
9 |
d. |
4 |
4 = 2127