If an angle between the line, 
and the plane, x−2y−kz=3 is cos−1
then a value of k is:
(a)
(b)
(c)
(d)
If an angle between the line, and the plane, x−2y−kz=3 is cos−1 then a value of k is:
(a)
(b)
(c)
(d)
Question ID - 57295 | SaraNextGen Top Answer
If an angle between the line, and the plane, x−2y−kz=3 is cos−1 then a value of k is:
(a)
(b)
(c)
(d)
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If an angle between the line, |
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(a) |
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(b) |
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(c) |
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(d) |
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1 Answer
127 votes
Answer Key / Explanation : (c) -
DR's of line are 2, 1, −2
normal vector of plane is 
– 2
– k
sin 
= 
sin 
= 
…(1)
cos 
= 
…(2)
(1)2 + (2)2 = 1 ⇒ k2 =
127 votes
Answer Link
127