If a circle of radius R passes through the origin O and intersects the coordinate axes at A and B, then the locus of the foot of perpendicular from O on AB is |
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(a) |
(x |
(b) |
(x |

(c) |
(x |
(d) |
(x |

If a circle of radius R passes through the origin O and intersects the coordinate axes at A and B, then the locus of the foot of perpendicular from O on AB is |
|||

(a) |
(x |
(b) |
(x |

(c) |
(x |
(d) |
(x |

1 Answer

127 votes

Slope of AB =

Equation of AB is h_{x}+k_{y} = h^{2} + k^{2}

A

AB = 2R

⇒ (h^{2} + k^{2})^{3} = 4R^{2}h^{2}k^{2}

⇒ (x^{2}+y^{2})^{3} = 4R^{2}x^{2}y^{2}

127 votes

127