The mean and the variance of five observations are 4 and 5.20, respectively. If three of the observations are 3, 4 and 4; then then absolute value of the difference of the other two observations, is
The mean and the variance of five observations are 4 and 5.20, respectively. If three of the observations are 3, 4 and 4; then then absolute value of the difference of the other two observations, is
mean = 4, 2 = 5.2, n = 5,. x1 =3 x2 = 4 = x3
x4 + x5 =9 ….(i)
= 2
⇒ = 106
….(ii)
Using (i) and (ii) (x4 – x5)2 = 49
|x4 – x5| = 7