Let O(0, 0) and A(0, 1) be two fixed points. Then the locus of a point P such that the perimeter of 
AOP is 4, is
(a)
8x2 − 9x2 + 9y = 18
(b)
9x2 + 8x2 − 8y = 16
(c)
9x2 − 8x2 + 8y = 16
(d)
8x2 + 9x2 − 9y = 18
Let O(0, 0) and A(0, 1) be two fixed points. Then the locus of a point P such that the perimeter of AOP is 4, is
(a)
8x2 − 9x2 + 9y = 18
(b)
9x2 + 8x2 − 8y = 16
(c)
9x2 − 8x2 + 8y = 16
(d)
8x2 + 9x2 − 9y = 18
Question ID - 57556 | SaraNextGen Top Answer
Let O(0, 0) and A(0, 1) be two fixed points. Then the locus of a point P such that the perimeter of AOP is 4, is
(a)
8x2 − 9x2 + 9y = 18
(b)
9x2 + 8x2 − 8y = 16
(c)
9x2 − 8x2 + 8y = 16
(d)
8x2 + 9x2 − 9y = 18
|
Let O(0, 0) and A(0, 1) be two fixed points. Then the locus of a point P such that the perimeter of |
|||
|
(a) |
8x2 − 9x2 + 9y = 18 |
(b) |
9x2 + 8x2 − 8y = 16 |
|
(c) |
9x2 − 8x2 + 8y = 16 |
(d) |
8x2 + 9x2 − 9y = 18 |
1 Answer
127 votes
Answer Key / Explanation : (b) -
Let point P(h, k)
OA = 1
So, OP + AP = 3
= 3
⇒ h2 + (k − 1)2 = 9 + h2 + k2 − 6
⇒ 6
= 2k + 8
⇒ 9
= k2 + 16 + 8k
⇒ 9h2 + 8k2 − 8k − 16 = 0
Locus of point P will be,
9x2 + 8y2 − 8y − 16 = 0
127 votes
Answer Link
127