Let A = , ( R) such that A^{32} = . Then a value of is 

(a) 

(b) 

(c) 
0 
(d) 

Let A = , ( R) such that A^{32} = . Then a value of is 

(a) 

(b) 

(c) 
0 
(d) 

A =
A^{2} = =
Then A^{4} = A^{2}.A^{2} =
similarly A^{8} = A^{4}.A^{4}=
and so on A^{32} = =
So sin32 = 1 and cos32 = 0
⇒ 32 = 2n +
⇒ = where n Z
put n = 0, α =