From a well shuffled ordinary deck of cards, 4 are drawn then which of the following is not correct?
a) The number of ways so that four cards of same suit = 2880
b) The number of ways so that cards are of different suits = 134
c) The number of ways so that all the four cards are face cards = 495
d) The number of ways so that drawn cards are of same colour = 2×26C4
Total number of cards in a ordinary deck = 52
Number of cards drawn = 4
(a) There are four suits (diamond, heart, spade and club) of 13 cards each.
∴ Number of ways of selecting a suit = 4
and from the selecting suit 4 cards can be drawn by 13
∴ Required number of ways = 4
13
= 2860
(b) As the cards are of different suits and each suit having 13 cards therefore number of ways of selecting one card from each suit = 13
∴ Required number of ways of selecting one card from each suit = 13
× 13
×13
×13
=
(c) There are 3 face cards (king, queen, knave) in each suit and there are 4 suits so total number of face cards in the deck = 12 and 4 can be selected by 12
ways
=
(d) There are two colours (black and red) each having 26 cards.
∴ Number of ways of selecting 4 cards of same colour = 26
26
=2×26
Hence, option (a) is not correct
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