Question ID - 99438 | SaraNextGen Top Answer
A man of mass 
is standing on a stationary flat car of mass
. The car can move without friction along horizontal rails. The man starts walking with velocity 
relative to the car. Work done by him
a)
Is greater than 
if he walks along rails
b)
Is less than
if he walks along rails
c)
In equal to 
if he walks normal to rails
d)
Can never be less than 
A man of mass is standing on a stationary flat car of mass . The car can move without friction along horizontal rails. The man starts walking with velocity relative to the car. Work done by him
a)
Is greater than if he walks along rails
b)
Is less than if he walks along rails
c)
In equal to if he walks normal to rails
d)
Can never be less than
(b,c)
If the man starts walking with velocity 
(relative to the car) along the rails, the car recoils. Let the velocity with which the car recoils be 
Then, resultant velocity of the man will be equal to 
Since the car moves without friction, there is no external horizontal force on the system of man and car. Hence, applying conservation of momentum, we get
Work done by the man is used to provide kinetic energy to the car and to the man himself
Hence work done by him
But 
is less than 
and 
both, therefore 
is less than 
. Hence, option a. is wrong and b. is correct
If the man moves normal to the rails, then the car will not move. Hence in that case, man moves along with velocity 
. Hence, work by him is used to provide kinetic energy to his own body which is equal to 
. Hence, option c. is correct. Since option b. is correct, option d. is wrong
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