Additional Questions
Question 1.
Find the range of the function.
$
f=\{(1, x),(1, y),(2, x),(2, y),(3, z)\}
$
Solution:
The range of the function is $\{x, y, z\}$.
Question 2.
For $\mathrm{n}, \mathrm{m} \in \mathrm{N}$, nln means that $\mathrm{tt}$ is a factor of $\mathrm{n} \& \mathrm{~m}$. Then find whether the given relation is an equivalence relation.
Solution:
Since $\mathrm{n}$ is a factor of $\mathrm{n}$. So the relation is reflexive.
When $\mathrm{n}$ is a factor of $\mathrm{m}$ (where $\mathrm{m} \neq \mathrm{n}$ ) then $\mathrm{m}$ cannot be a factor of $\mathrm{n}$.
So the relation is not symmetric when $n$ is a factor of $m$ and $m$ is a factor of $\mathrm{p}$ then $n$ will be a factor of $\mathrm{p}$. So the given relation is transitive. So it is not an equivalence relation.
Question 3.
Verify whether the relation "is greater than" is an equivalence relation.
Solution:
You can do it yourself.