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Page No 166: - Chapter 12 Sound class 9 ncert solutions Science - SaraNextGen [2024]


Question 1:

Which wave property determines (a) loudness, (b) pitch?

Answer:

(a) Amplitude (b) Frequency

(a) The loudness of a sound depends on its amplitude. If the amplitude of a sound is large, then the sound produced will also be loud.

(b) The pitch of a sound depends on its frequency. A sound will be considered a high pitched sound, if its frequency is high.

 

 

Question 1:

What are wavelength, frequency, time period and amplitude of a sound wave?

Answer:

Wavelength: The distance between two consecutive compressions or two consecutive rarefactions is known as the wavelength. Its SI unit is metre (m).

Frequency: The number of complete oscillations per second is known as the frequency of a sound wave. It is measured in hertz (Hz).

Amplitude: The maximum height reached by the crest or trough of a sound wave is called its amplitude.

 

 

Question 1:

Distinguish between loudness and intensity of sound.

Answer:

Intensity of a sound wave is defined as the amount of sound energy passing through a unit area per second. Loudness is a measure of the response of the ear to the sound. The loudness of a sound is defined by its amplitude. The amplitude of a sound decides its intensity, which in turn is perceived by the ear as loudness.

 

 

Question 2:

Guess which sound has a higher pitch: guitar or car horn?

Answer:

The frequency of the vibration of a sound produced by a guitar is greater than that produced by a car horn. Since the pitch of a sound is proportional to its frequency, the guitar has a higher pitch than a car horn.

 

 

Question 2:

How are the wavelength and frequency of a sound wave related to its speed?

Answer:

Speed, wavelength, and frequency of a sound wave are related by the following equation:

Speed (https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1278/Chapter%2012_html_mff52ae1.gif ) = Wavelength (https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1278/Chapter%2012_html_m11cc021f.gif ) × Frequency (https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1278/Chapter%2012_html_m5aaabc6e.gif )

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1278/Chapter%2012_html_m57c0bd5e.gif

 

Question 3:

Calculate the wavelength of a sound wave whose frequency is 220 Hz and speed is 440 m/s in a given medium.

Answer:

Frequency of the sound wave, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1280/Chapter%2012_html_m5aaabc6e.gif = 220 Hz

Speed of the sound wave, = 440 m s−1

For a sound wave,

Speed = Wavelength × Frequency

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1280/Chapter%2012_html_77d60dc1.gif

Hence, the wavelength of the sound wave is 2 m.

 

 

Question 4:

A person is listening to a tone of 500 Hz sitting at a distance of 450 m from the source of the sound. What is the time interval between successive compressions from the source?

Answer:

The time interval between two successive compressions is equal to the time period of the wave. This time period is reciprocal of the frequency of the wave and is given by the relation:

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1282/Chapter%2012_html_m28681f24.gif

Also Read : Page-No-167:-Chapter-12-Sound-class-9-ncert-solutions-Science

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