In-Text Questions Try These (Text book Page No. 40, 41, 42, 43,44) - Chapter 3 Perimeter and Area Term 3 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

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On April 24, 2024, 11:35 AM

Try this (Text book Page No. 40 ) : Chapter 3 Perimeter and Area Term 3 Class 6th std Maths Guide Samacheer Kalvi Solutions
Question $1 .$
Is the perimeter of the given shape possible ? why ?

Solution:
Not possible. Because perimeter is the length of the boundaries of any closed shape. It is not a closed shape.

Try These  (Text book Page No.41)

Question $1 .$
Draw a shape with perimeter $16 \mathrm{~cm}$ in a dot sheet

Solution:

Question $2 .$
What is the perimeter of a rectangle if the length is twice its breadth?
Solution:
Perimeter of a rectangle $=2(1+b)$ units
$=2 \times(2 \mathrm{~b}+\mathrm{b})$ units
$=2 \times 3 \mathrm{~b}$ units $=6 \mathrm{~b}$ units
Perimeter of a rectangle $=6 \mathrm{~b}$ units.
 

Question $3 .$
What would be the perimeter of a square if its side is reduced to half?
Solution:
Let a side of a square $=s$ units.
If $s$ is reduced to half then its side $=\frac{s}{2}$ units
Then perimeter of a square $=(4 \times$ side $)$ units $=4 \times \frac{\mathrm{s}}{2}$ units
$=2 \mathrm{~s}$ units
 

Question $4 .$
What is the perimeter of a triangle if all sides are equal in length?
Solution:
Perimeter of a triangle $P=$ sum of its 3 sides.
If all sides are equal, it is an equilateral triangle with side say a.
Perimeter $=a+a+a$ units $=3 a$ units

Try this (Text book Page No. 42 )
Question $1 .$

Can different shapes have the same perimeter
Solution:
Yes, different shapes can have the same perimeter.

Try These (Text book Page No. 43)
Question $1 .$
Find the breadth of the rectangle with perimeter $14 \mathrm{~m}$ and length $4 \mathrm{~m}$.
Solution:
Given perimeter of the rectangle $\mathrm{P}=14 \mathrm{~m}$

length $\mathrm{l}=4 \mathrm{~m}$
Perimeter of a rectangle $\mathrm{P}=2 \times(l+b)$ units.
$\begin{aligned}
14 &=2 \times(4+b) \mathrm{m} \\
\frac{14}{2} &=4+b \\
7 &=4+b \\
b &=7-4=3 \mathrm{~m}
\end{aligned}$
Breadth of the rectangle $b=3 \mathrm{~m}$.

Question $2 .$
The perimeter of an isosceles triangle is $21 \mathrm{~cm}$. Find the measure of equal sides given that the third side is $5 \mathrm{~cm}$.
Solution:
Perimeter of the triangle $P=(a+b+c)$ units.
$21=[(a+b)+5] \mathrm{cm}$
$21-5=a+b$
$16=a+b$
Here $\mathrm{a}$ and $\mathrm{b}$ are equal sides and let $\mathrm{a}=\mathrm{b}$
$16=a+a$
$\begin{aligned}
&2 \mathrm{a}=16 \\
&a=\frac{16}{2} \\
&\mathrm{a}=8 \mathrm{~cm} .
\end{aligned}$
$\therefore$ Equal sides measure $8 \mathrm{~cm}$.

Try these (Text book Page No. 44)
Question $1 .$
Find the number of tiles required to fill the area of following figures

Solution:
i) Total number of tiles required $=16$
Number of tiles already filled $=7$
Remaining required tiles $=16-7=9$
ii) Total number of tiles required $=12$
Number of tiles already filled $=6$
Remaining required tiles $=12-6=6$
iii) Total number of tiles required $=12$
Number of tiles already filled $=6$
Remaining required tiles $=12-6=6$
iv) Total number of tiles required $=16$
Number of tiles already filled $=8$
Remaining required tiles $=16-8=8$