Text Book Back Questions and Answers - Chapter 11 Transport in Plants 11th Biology Botany Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

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On April 24, 2024, 11:35 AM

Transport in Plants
Text Book Back Questions and Answers
I. Choose the correct answers.
Question 1.
In a fully turgid cell:
(a) $\mathrm{DPD}=10$ atm; $\mathrm{OP}=5 \mathrm{~atm} ; \mathrm{TP}=10 \mathrm{~atm}$
(b) $D P D=0$ atm; $O P=10$ atm; $T P=10$ atm
(c) $\mathrm{DPD}=0 \mathrm{~atm} ; \mathrm{OP}=5 \mathrm{~atm} ; \mathrm{TP}=10 \mathrm{~atm}$
(d) $\mathrm{DPD}=20 \mathrm{~atm} ; \mathrm{OP}=20 \mathrm{~atm} ; \mathrm{TP}=10 \mathrm{~atm}$
Answer:
(b) $\mathrm{DPD}=0 \mathrm{~atm} ; \mathrm{OP}=10 \mathrm{~atm} ; \mathrm{TP}=10 \mathrm{~atm}$
Question 2.
Which among the following is correct?
(i) Apoplast is fastest and operate in nonliving part
(ii) Trahsmembrane route includes vacuole
(iii) Symplast interconnect the nearby cell through plasmadesmata
(iv) Symplast and transmembrane route are in living part of the cell
(a) (i) and (ii) only
(b) (ii) and (iii) only
(c) (iii) and (iv) only
(d) All of these
Answer:
(c) (iii) and (iv) only
Question 3.
What type of transpiration is possible in the xerophyte Opuntia?
(a) Stomatal
(b) Lenticular
(c) Cuticular
(d) All the above
Answer:
(b) Lenticular

Question 4.
Stomata of a plant open due to:
(a) Influx of $\mathrm{K}^{+}$
(b) Efflux of $\mathrm{K}+$
(c) Influx of $\mathrm{Cl}$
(d) Influx of $\mathrm{OH}^{-}$
Answer:
(a) Influx of $\mathrm{K}^{+}$
Question 5.
Munch hypothesis is based on:
(a) translocation of food due to TP gradient and imbibition force
(b) ranslocation of food due to TP
(c) translocation of food due to imbibition force
(d) None of the above
Answer:
(b) ranslocation of food due to TP
Question 6.
If the concentration of salt in the soil is too high and the plants may wilt even if the field is thoroughly irrigated. Explain.
Answer:
The salts present in the soil dissolve in the irrigated water and form hypertonic solution outside the root hairs of the plant and the root hairs cannot absorb water from hypertonic solution, since water molecules cannot move from hypertonic solution to hypotonic solution in the cells of root hair. Hence the plants become wilt even the field is irrigated.
Question 7.
How phosphorylase enzyme open the stomata in starch sugar interconversion theory?
Answer:
The discovery of enzyme phosphorylase in guard cells by Hanes (1940) greatly supports the starch - sugar interconversion theory. The enzyme phosphorylase hydrolyses starch into sugar and high $\mathrm{pH}$ followed by endosmosis and the opening of stomata during light. The vice versa takes place during the night.

Question 8.
List out the non photosynthetic parts of a plant that need a supply of sucrose?
Answer:
The non photosynthetic parts of a plant that need a supply of sucrose:
1. Roots
2. Tubers
3. Developing fruits and
4. Immature leaves.
Question 9.
What are the parameters which control water potential?
Answer:
Water potential $(\Psi)$ can be controlled by,
1. Solute concentration or Solute potential $\left(\Psi_s\right)$
2. Pressure potential $\left(\Psi_{\mathrm{p}}\right)$.
By correlating two factors, water potential is written as, $\Psi_{\mathrm{w}}=\Psi_{\mathrm{s}}+\Psi_{\mathrm{p}}$. Water Potential $=$ Solute potential + Pressure potential.
Question 10.
An artificial cell made of selectively permeable membrane immersed in a beaker (in the figure). Read the values ans answer the following questions?

$
\Psi_{\mathrm{w}}=0, \Psi_{\mathrm{s}}=2, \Psi_{\mathrm{p}}=0
$
(a) Draw an arrow to indicate the direction of water movement.
(b) Is the solution outside the cell isotonic, hypotonic or hypertonic?
(c) Is the cell isotonic, hypotonic or hypertonic?
(d) Will the cell become more flaccid, more turgid or stay in original size?
(e) With reference to artificial cell state, the process is endosmosis or exosmosis? Give reasons.
Answer:
(a) An arrow to indicate the direction of water movement:

(b) Outside solution in hypotonic.
(c) The cell is hypertonic.
(d) The cell become more turgid.
(e) The process is endo - osmosis because the solvent (water) moves inside the cell.