In-Text Questions (Textbook Page No. 55) - Chapter 3 Ratio and Proportion Term 1 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

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On April 24, 2024, 11:35 AM

In-Text Questions : Chapter 3 Ratio and Proportion Term 1 Class 6th std Maths Guide Samacheer Kalvi Solutions
Recap (Textbook Page No. 55)
Question $1 .$
Which of the following fractions is not a proper fraction?
(a) $\frac{1}{3}$
(b) $\frac{2}{3}$
(c) $\frac{5}{10}$
(d) $\frac{10}{5}$
Solution:
(d) $\frac{10}{5}$

Question 2 .
The equivalent fraction of $\frac{1}{7}$ is
(a) $\frac{2}{15}$
(b) $\frac{1}{49}$
(c) $\frac{7}{49}$
(d) $\frac{100}{7}$
Solution:
(c) $\frac{7}{49}$

Question $3 .$
Write $>,<$ or $=$ in the box.
(i) $\frac{5}{8}_{-} \frac{1}{10}$
(ii) $\frac{9}{12} \ldots \frac{3}{4}$
Solution:

(i) $\frac{8}{5}=\frac{5 \times 10}{8 \times 10}=\frac{50}{80}$
$\frac{1}{10}=\frac{1 \times 8}{10 \times 8}=\frac{8}{80}$
Here $\frac{50}{80}>\frac{8}{80} \quad \therefore \frac{5}{8} \nabla \frac{1}{10}$
(ii) $\frac{9}{12} \equiv \frac{3}{4}$
$\frac{3}{4}=\frac{3 \times 3}{4 \times 3}=\frac{9}{12}$
Here $\frac{9}{12}=\frac{9}{12} \quad \therefore \frac{9}{12} \equiv \frac{3}{4}$

Question $4 .$
Arrange these fractions from the least to the greatest: $\frac{1}{2}, \frac{1}{4}, \frac{6}{8}, \frac{1}{8}$
Solution:
$\begin{aligned}
&\frac{1}{2}=\frac{1 \times 4}{2 \times 4}=\frac{4}{8} \\
&\frac{1}{4}=\frac{1 \times 2}{4 \times 2}=\frac{2}{8}
\end{aligned}$
Comparing $\frac{4}{8}, \frac{2}{8}, \frac{6}{8}$ and $\frac{1}{8}$. we have $\frac{1}{8}<\frac{2}{8}<\frac{4}{8}<\frac{6}{8}$ i.e, $\frac{1}{8}<\frac{1}{4}<\frac{1}{2}<\frac{6}{8}$

Question 5 .
Annan says the $\frac{2}{6}$ th of the group of triangles given below are blue. Is he correct?

Solution:
No, he is not correct because of the total of 6 triangles 4 are blue, i.e 4/6 triangles are blue.

Question $6 .$
Joseph has a flower garden. Draw a picture which shows that 2/10th of the flowers are red and the rest of them are yellow.

Solution

Question $7 .$
Malarkodi has 10 oranges. If she ate 4 oranges, what fraction of oranges she was not eaten by her?
Solution:
$\frac{\text { Oranges not eaten }}{\text { Total oranges }}=\frac{10-4}{10}=\frac{6}{10}$

Question $8 .$
After sowing seeds on day one, Muthu observes the growth of two plants and records it. In 10 days, if the first plant grew $\frac{1}{4}$ th of an inch and the second plant grew $\frac{3}{8}$ th of an inch, then which plant grew more?
Solution:
Comparing $\frac{1}{4}$ th of an inch and $\frac{3}{8}$ th of an inch.
$\frac{1}{4}=\frac{2}{8}<\frac{3}{8}$
Second plant grew more.