Exercise 2.2 - Chapter 2 Measurements Term 2 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

Updated By SaraNextGen

On April 24, 2024, 11:35 AM

Question $1 .$
Say the time in two ways:

Solution:
(i) $10: 15$ hours; quarter past $10 ; 45$ minutes to 11
(ii) $6: 45$ hours; quarter to $7 ; 45$ minutes past 6
(iii) $4: 10$ hours; 10 minutes past $4 ; 50$ minutes to 5
(iv) $3: 30$ hours; half-past $3 ; 30$ minutes to 4
(v) $9: 40$ hours; 20 minutes to $10 ; 40$ minutes past 9 .

Question $2 .$
Match the following:
(i) $9.55$ - (a) 20 minutes past 2
(ii) $11.50-$ (b) quarter past 4
(iii) $4.15$ - (c) quarter to 8
(iv) $7.45$ - (d) 5 minutes to 10
(v) $2.20$ - (e) 10 minutes to 1 ?
Solution:
(i) $9.55-$ (d) 5 minutes to 10
(ii) $11.50$ - (e) 10 minutes to 12
(iii) $4.15$ - (b) quarter past 4
(iv) $7.45-$ (c) quarter to 8
(v) $2.20$ - (a) 20 minutes past 2

Question $3 .$
Convert the following :
(i) 20 minutes into seconds

(ii) 5 hours 35 minutes 40 seconds into seconds
(iii) $3 \frac{1}{2}$ hours into minutes
(iv) 580 minutes into hours
(v) 25200 seconds into hours
Solution:
(i) 20 minutes into seconds
20 minutes $=20 \times 60$ seconds $=1200$ seconds
(ii) 5 hours 35 minutes 40 seconds into seconds

$\therefore 5$ hours 35 minutes 40 seconds $=20,140$ seconds
(iii) $3 \frac{1}{2}$ hours into minutes
$3 \frac{1}{2}$ hours $=3$ hours 30 minutes
$=3 \times 60$ minutes $+30$ minutes
$=180$ minutes $+30$ minutes
$=210$ minutes
$\therefore 3 \frac{1}{2}$ hours $=210$ minutes
(iv) 5580 minutes into hours
580 minutes $=\frac{580}{60}$ hours $=9$ hours 40 minutes
$\therefore 580$ minutes $=9$ hours 40 minutes
(v) 25200 seconds into hours
25200 seconds $=\frac{25200}{60}$ minutes $=420$ minutes $=\frac{420}{60}$ hours $=7$ hours
$\therefore 25200$ seconds $=7$ hours

Question $4 .$
The duration of electricity consumed by the farmer for his pumpset on Monday and Tuesday was 7 hours 20 minutes 35 seconds and 3 hours 44 minutes 50 seconds respectively. Find the total duration of consumption of electricity.
Solution:
Total duration of electricity consumed on both the days
$=7$ hours $20 \mathrm{~min} 35 \mathrm{sec}+3$ hours $44 \mathrm{~min} 50 \mathrm{sec}$
$=(7+3)$ hours $(20+44) \min (35+50) \sec$
$=10$ hours $64 \mathrm{~min} 85$ seconds
$=11$ hours $5 \mathrm{~min} 25$ seconds

Question $5 .$
Subtract $10 \mathrm{hrs} 20 \mathrm{~min} 35 \mathrm{sec}$ from $12 \mathrm{hrs} 18 \mathrm{~min} 40 \mathrm{sec}$.
Solution:

Question $6 .$
Change the following into 12 hour format:
(i) $02: 00$ hours
(ii) $08: 45$ hours
(iii) $21: 10$ hours
(iv) $11: 20$ hours
(v) $00: 00$ hours
Solution:

Question 7.
Change the following into 24 hour format.
(i) $3.15$ a.m.
(ii) $12.35 \mathrm{p} \cdot \mathrm{m}$.
(iii) $12.00$ noon
(iv) $12.00$ midnight.

Solution:

Question $8 .$
Calculate the duration of time.
(i) from $5.30$ a.m to $12.40$ p.m
(ii) from $1.30$ p.m to $10.25$ p.m
(iv) from 17:00 hours to $5: 15$ hours
Solution:
(i) from $5.30$ a.m. to $12.40$ p.m.
Duration of time from $5.30 \mathrm{a} \cdot \mathrm{m}$. to noon $=12: 00-5: 30=6: 30$ i.e 6 hours 30 minutes
From noon to $12.40$ p.m the duration $=00$ hours 40 minutes
Total duration $=6$ hours 30 minutes $+00$ hours 40 minutes
$=6$ hours 70 minutes
$=6$ hours $+(60+10)$ minutes
$=6$ hours $+1 \mathrm{hr} 10$ minutes
$=7$ hours 10 minutes
$\therefore$ Duration of time from $5.30$ am to $12.40 \mathrm{pm}=7$ hours 10 minutes
(ii) from $1.30 \mathrm{pm}$ to $10.25$ p.m.
10 hours 25 minutes
Duration of time $=9$ hours 85 minutes

Duration of time $=8 \mathrm{hrs} 55 \mathrm{~min}$.
(iii) from $20: 00 \mathrm{hrs}$ to $4: 00 \mathrm{hrs}$.

Question $9 .$
The departure and arrival timing of the Vaigai Superfast Express (No. 12635) from Chennai Egmore to Madurai Junction are given. Read the details and answer the following.

(i) At what time does the Vaigai Express start from Chennai and arrive at Madurai?
(ii) How many halts are between there Chennai and Madurai?
(iii) How long does the train halt at the Villupuram junction?
(iv) At what time does the train come to Sholavandan?
(v) Find the journey time from Chennai Egmore to Madurai?
Solution:
(i) It starts from Chennai at $13: 40 \mathrm{hrs}$ and arrive at Madurai at $21: 20 \mathrm{hrs}$.
(ii) There are 8 halts.
(iii) Departure from Villupuram $=15$ hours 55 minutes
Arrival at Villupuram $=15$ hours 50 minutes
The train halt at Villupuram for $=05$ minutes
(iv) At $20: 34$ hours the train come to Sholavandan

(v) Arrival time at Madurai $=20$ hours $80(20+60)$ minutes
Departure time from Chennai Egmore $=13$ hours 40 minutes
Journey Time $=07$ hours 40 minutes

Question $10 .$
Manickam joined a chess class on $20.02 .2017$ and due to exam, he left practice after 20 days. Again he continued practice from $10.07 .2017$ to $31.03 .2018$. Calculate how many days did he practice?
Solution:
From the date of joining $=20$ days From $10.07 .2017$ to $31.03 .2018$
July $-22$
Aug $-31$
Sep $-30$
$\mathrm{Oct}-31$
Nov $-30$
Dec $-31$
$\operatorname{Jan}-31$
Feb $-28$
Mar - 31
Total $-265$
Total no of practice days $=265+20=285$ days

Question $11 .$
A clock gains 3 minutes every hour. If the clock is set correctly at 5 a.m, find the time shown by the clock at 7 p.m?
Solution:
5 a.m. $=5.00$ hours
7 p.m $=19.00$ hours
Difference $=19.00-5.00=14.00$ hours
Time gain $=14 \times 3=42$ minutes
Time shown by the clock $=7.42$ p.m

Question $12 .$
Find the number of days between the republic day and kalvi valarchi day in 2020 .
Solution:
2020 is a leap year republic day $-26.01 .2020$
Kalvi valarchi day $-15.07 .2020$
Jan $-5$
Feb $-29$
Mar-31
April $-30$
May $-31$
June $-30$
July $-14$
Total $-170$ days

Question $13 .$
If 11 th of January 2018 is Thursday, what is the day on 20 th July of the same year?

Solution:
January - 21 Days $(31-10)$
February - 28 Days
March - 31 Days
April $-30$ Days
May - 31 Days
June $-30$ Days
July - 19 Days
Total - 190 Days
190 days $\div 7$
190 days $=27$ weeks $+1$ day
Required day is the first day after Thursday.
$\therefore 20$ th of July is Friday.

Question $14 .$
(i) Convert 480 days into years
(ii) Convert 38 months into years
Solution:
(i) 480 days $=\frac{480}{365}$
$=1$ year 115 days
$=1$ year 3 months 25 days
(ii) 38 months $=\frac{38}{12}$
$=3$ years 2 months

Question $15 .$
Calculate your age as on $01.06 .2018$
Solution:

Objective Type Questions
Question $16 .$
2 days $=\ldots \ldots$ hours
(i) 38
(ii) 48
(iii) 28
(iv) 40
Solution:
(ii) 48

Question $17 .$
3 weeks = days.
(a) 21
(b) 7
(c) 14
(d) 28
Solution:
(a) 21

Question $18 .$
Number of ordinary years between two consecutive leap years is
(i) 4 years
(ii) 2 years
(iii) 1 year
(iv) 3 years
Solution:
(iv) 3 years

Question $19 .$
What time will it 5 hours after $22: 35$ hours?
(a) $2: 30 \mathrm{hrs}$
(b) $3: 35$ hrs
(c) $4: 35$ hrs
(d) $5: 35 \mathrm{hrs}$
Solution:
(b) $3: 35$ hrs

Question 20 .
$2 \frac{1}{2}$ years is equal to months.
(i) 25
(ii) 30
(iii) 24
(iv) 5
Solution:
(ii) 30