Additional Questions - Chapter 2 Measurements Term 2 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

Updated By SaraNextGen

On April 24, 2024, 11:35 AM

Additional Questions
Question $1 .$
Convert into indicated units: $200 \mathrm{mg}$ into $\mathrm{g}$.
Solution:
$200 \mathrm{mg}=200.0 \times \frac{1}{1000}=0.2 \mathrm{~g}$

Question $2 .$
(a) What are the universally accepted basic metric units?
(b) A cow gives 10 litres of milk in the morning and 8 litres in the evening. Find the total milk it gives for a week in ml?
Solution:
(a) Universally accepted basic metric units are:
Length in metre, Weight in gram and Capacity (Volume) in litre.
(b) Litres of milk the cow gives in the morning $=101$.
Litres of milk the cow gives in the evening $=81$.
Total milk per day $=10+8=181$
Total milk for a week $=18 \times 7 \mathrm{l}=126 \mathrm{l}=126 \times 1000 \mathrm{ml}=126000 \mathrm{ml}$.
Total milk the cow gives for a week $=1,26,000 \mathrm{ml}$.

Question $3 .$
A box contains $20 \mathrm{~kg} 280 \mathrm{~g}$ of sugar. After transferring into a smaller box of $2 \mathrm{~kg} 720 \mathrm{~g} 7$ times find the remaining sugar left in the big box in $\mathrm{cg}$.
Solution:
Total sugar in the box $=20 \mathrm{~kg} 280 \mathrm{~g}$.
Measurement of smaller box $=2 \mathrm{~kg} 720 \mathrm{~g}$.
7 times the smaller box $=2 \mathrm{~kg} 720 \mathrm{~g} \times 7=19 \mathrm{~kg} 040 \mathrm{~g}$.
Remaining sugar $=20 \mathrm{~kg} 280 \mathrm{~g}-19 \mathrm{~kg} 40 \mathrm{~g}=1 \mathrm{~kg} 240 \mathrm{~g}=1240 \mathrm{~g} .=1240 \times 100 \mathrm{cg}=124000 \mathrm{eg}$.
Sugar left in the box $=1,24,000 \mathrm{eg}$.

Question $4 .$
Sneha needs $1 \mathrm{~m} 20 \mathrm{~cm}$ of cloth for her blouse. If she bought 20 such cloths find the total cloth she bought in $\mathrm{cm}$ ?
Solution:
For one blouse the cloth needed $=1 \mathrm{~m} 20 \mathrm{~cm}$
Cloth needed for 20 blouse $=1 \mathrm{~m} 20 \mathrm{~cm} \times 20$
$=20 \mathrm{~m} 400 \mathrm{~cm}$
$=20 \times 100+400 \mathrm{~cm}$
$=2000+400 \mathrm{~cm}$
$=2400 \mathrm{~cm}$.
Total cloth bought $=2400 \mathrm{~cm}$.

Question $5 .$
Can you add $2 \mathrm{~m} 20 \mathrm{~cm}$ and $4 \mathrm{~kg} 80 \mathrm{~g}$ ? Why?
Solution:
No, we can't. To add or subtract, the measures should be in the same unit.

Question $6 .$
If you serve a cup of coffee measuring $150 \mathrm{ml}$ each for 200 people find the volume of coffee needed in litres?
Solution:
For one cup of coffee it needs $150 \mathrm{ml}$.
For 200 people it needs $150 \times 200 \mathrm{ml}=30000 \mathrm{ml}=30000 \times \frac{1}{1000} \mathrm{l}=30 \mathrm{l}$
Coffee needed $=301$.

Question $7 .$
A lorry full of fertiliser is bought to the garden having 120 coconut trees. If the lorry contain 1920 $\mathrm{kg}$, then find the measure of fertiliser each coconut tree can have?
Solution:
Total measure of fertiliser $=1920 \mathrm{~kg}$.
Number of coconut tress $=120$
For one tree $=\frac{1920}{120} \mathrm{~kg}=16 \mathrm{~kg}$.
One tree can have $16 \mathrm{~kg}$ of fertiliser

Question $8 .$
Convert $7 \mathrm{~kg} 250 \mathrm{~g}$ in to $\mathrm{mg}, \mathrm{g}$ and $\mathrm{cg}$ ?
Solution:
$7 \mathrm{~kg} 250 \mathrm{~g}$.
(i) $7 \mathrm{~kg} 250 \mathrm{~g}=7 \times 1000+250 \mathrm{~g}$. $=7000+250=7250 \mathrm{~g}$.
(ii) $7 \mathrm{~kg} 250 \mathrm{~g}=7250 \mathrm{~g} .=7250 \times 1000 \mathrm{mg}=72,50,000 \mathrm{mg}$.
(iii) $7 \mathrm{~kg} 250 \mathrm{~g}=7250 \mathrm{~g}$. $=7250 \times 100 \mathrm{cg}=7,25,000 \mathrm{cg}$.

Question $9 .$
Convert $20 \mathrm{~m} 20 \mathrm{~cm}$ into $\mathrm{cm}, \mathrm{m}$ and $\mathrm{km}$.
Solution:
$20 \mathrm{~m} 20 \mathrm{~cm}$.
(i) $20 \mathrm{~m} 20 \mathrm{~cm}=20 \times 100+20 \mathrm{~cm}=2000+20 \mathrm{~cm}=2020 \mathrm{~cm}$
(ii) $20 \mathrm{~m} 20 \mathrm{~cm}=2020 \mathrm{~cm}=2020 \times \frac{1}{100} \mathrm{~m}=20.20 \mathrm{~m}$
(iii) $20 \mathrm{~m} 20 \mathrm{~cm}=20.20 \mathrm{~m}=20.20 \times \frac{1}{1000} \mathrm{~km}=0.02020 \mathrm{~km}$
 

Question $10 .$
Convert $851720 \mathrm{ml}$ into $\mathrm{ml}$, l and kl?
Solution:
$851720 \mathrm{ml}$
(i) $851720 \mathrm{ml}=85 \times 1000+720 \mathrm{ml}=85000+720 \mathrm{ml}=85,720$
(ii) $851720 \mathrm{ml}=85 \mathrm{l}+720 \times \frac{1}{1000} \mathrm{l}=85 \mathrm{l}+0.720 \mathrm{l}=85.72 \mathrm{l}$.
(iii) $851720 \mathrm{ml}=85.72 \mathrm{l}=85.72 \times \frac{1}{1000} \mathrm{kl}=0.08572 \mathrm{kl}$.

Question $11 .$
Which is greater $0.007 \mathrm{~g}, 0.7 \mathrm{~kg}$ or $70 \mathrm{mg}$ ?
Solution:
$0.007 \mathrm{~g}=0.007 \times 1000 \mathrm{mg}=7 \mathrm{mg}$
$0.7 \mathrm{~kg}=0.7 \times 10,00,000 \mathrm{mg}=7,00,000 \mathrm{mg}$
$70 \mathrm{mg}=70 \mathrm{mg}$
$\therefore 0.7 \mathrm{~kg}$ is greater.

Question $12 .$
A bus leaves for Kanchipuram from Chennai at $4.30$ p.m. It takes $1 \mathrm{hr} 25 \mathrm{~min}$. to reach there. At what time will it reach at Kanchipuram?
Solution:
Starting time from Chennai $=4: 30 \mathrm{pm}$.
Duration of travel $=01 \mathrm{hr}: 25 \mathrm{~min}$
Arrival at Kanchipuram $=5: 55 \mathrm{pm}$
The bus will reach Kanchipuram at $5: 55 \mathrm{pm}$.
 

Question $13 .$
The duration of a film show is 3 hrs $15 \mathrm{~min}$. It starts at $6: 30 \mathrm{p} . \mathrm{m}$. When will it end?
Solution:
The film starts at $=6: 30 \mathrm{pm}$.
Duration of the film show $=3 \mathrm{hr}: 15 \mathrm{~min}$
The show end at $=9: 45$ p.m.

Question $14 .$
A train arrive Chennai Central at $11: 55 \mathrm{am}$. It reached Chennai $1 \mathrm{hr} 25 \mathrm{~min}$ late. What is the scheduled arrival time of the train at Chennai?
Solution:
The train arrived Chennai at $11: 55 \mathrm{am}=11: 55$ hours
The train is late by $=1$ hour $25 \mathrm{~min}$
Scheduled Time $=10: 30$ hours
The scheduled arrival time $=10.30$ a.m

Question $15 .$
Raju visited a fashion show. He stayed there for $2 \mathrm{hr} 30 \mathrm{~min}$ and came back to home. If he reached in the fashion show at $8: 45 \mathrm{pm}$. When did he leave for his home?
Solution:
Raju reached the fashion show at $8: 45$ p.m
He stayed there for $2 \mathrm{hr}: 30 \mathrm{~min}$
He will leave the show at $10: 75 \mathrm{~min}$
$=10 \mathrm{hr} 75 \mathrm{~min}$
$=10 \mathrm{hrs}(60+15) \mathrm{min}$
$=10 \mathrm{hrs}+1 \mathrm{hr} 15 \mathrm{~min}$
$=11 \mathrm{hrs} 15 \mathrm{~min}$
Raju will leave the show at $11: 15$ p.m

Question $16 .$
Mammalia travelled $4 \mathrm{hrs} 45 \mathrm{~min}$ by bus and $4 \mathrm{hrs} 45 \mathrm{~min}$ by train. Calculate the time she spent in travelling?
Solution:
Time travelled by bus $=4 \mathrm{hrs} 45 \mathrm{~min}$
Time travelled by train $=4 \mathrm{hrs} 45 \mathrm{~min}$
Total time she travelled $=8 \mathrm{hrs} 90 \mathrm{~min}$
$=8 \mathrm{hrs}(60+30) \mathrm{min} 8 \mathrm{hrs}+1 \mathrm{hr} 30 \mathrm{~min}$
Total time she travelled $=9 \mathrm{hr} 30 \mathrm{~min}$

Question $17 .$
David left home at $4: 30$ p.m to meet his friend. He came back after $3 \mathrm{hr} 25 \mathrm{~min}$ At what time did he came back?
Solution:
Time at which David left home $=4: 30$ p.m.
Time he spent outside $=3 \mathrm{hr}: 25 \mathrm{~min}$
Time at which he came back $=7: 55$ p.m
 

Question $18 .$
Malar reached her school at $7: 30$ a.m. and left for home at $12: 45$ p.m. How long did she stay in school?
Solution:
Malar left for home at $12: 45$ p.m. $=12: 45 \mathrm{hrs}$
She reached school at $=7: 30 \mathrm{hrs}$
She stayed at school for $=5: 15 \mathrm{hrs}$

Question $19 .$
Mathi's date of birth was $25.07 .2000$. What is her age on $29.08 .2017 ?$
Solution:
Convert the given date in YY MM DD format
Age $=2017.08 .29$
Date of birth $=2000.07 .25$
Age $=17.01 .04$
She is 17 years one month 04 days old.

Question 20 .
Find whether 2000,2018 and 2012 are leap years or not.
Solution:
2000 is a leap year (divisible by 400 )
2018 is a not leap year (not divisible by 4 )
2012 is a leap year (divisible by 4 )
 

Question 21 .
Find the railway time for $12: 05$ a.m, $4: 20 \mathrm{pm}$
Solution:
$12: 05$ am is $00: 05 \mathrm{hrs}$
$4: 20$ p.m. is $(12+4): 20 \mathrm{hrs}=16: 20 \mathrm{hrs}$