In-Text Questions (Try These Textbook Page No. 2,4,7) - Chapter 1 Fractions Term 3 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

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On April 24, 2024, 11:35 AM

Question $1 .$ : Chapter 1 Fractions  Term 3 Class 6th std Maths Guide Samacheer Kalvi Solutions
If all the three cakes are divided among the total participants of the function what would be cach one's share? Discuss.
Solution:
Total participants of the function $=9$
Total number of cakes $=3$
$\therefore$ Each cake should be divided into 3 equal parts.
$\therefore$ Total number of equal parts of cake $=9$
$\therefore$ Each one's share may be $\frac{1}{9}$ of total cakes or $\frac{1}{3}$ of a cake.

Question 2 .
Observe the following and represent the shaded parts as fraction.

Solution:
(i) Total number of equal parts $=8$
Shaded Parts = 3
Fraction representing the shaded parts $=\frac{3}{8}$
(ii) Total number of equal parts $=15$
Shaded parts $=5$
$\therefore$ Fraction representing the shaded parts $=\frac{5}{15}$

(iii) Total number of equal parts $=9$
Shaded parts $=3$
$\therefore$ Fraction representing the shaded parts $=\frac{3}{9}$
(iv) Total number of equal parts $=9$
Shaded parts $=5$
Fraction representing the shaded parts $=\frac{5}{9}$
 

Question $3 .$
Look at the following beakers, express the quantity of water as fraction and arrange them in ascending order:

Solution:
Quantity of water in the first beaker $=1$ full Quantity of water in the second beaker $=\frac{1}{4}$
Quantity of water in the third beaker $=\frac{3}{4}$
Quantity of water in the fourth beaker $=\frac{1}{2}$
Ascending order $\frac{1}{4}<\frac{1}{2}<\frac{3}{4}<1$
 

Question $4 .$
Write the fraction of shaded part in the following.

Solution:

(i) Total number of equal parts $=3$
Shaded parts $=2$
Fraction representing the shaded portion $=\frac{2}{3}$
(ii) Total number of equal parts $=4$
Shaded parts $=3$
Fraction representing the shaded parts $=\frac{3}{4}$
(iii) Total number of equal parts $=5$
Shaded parts $=4$
Fraction representing the shaded parts $=\frac{4}{5}$
 

Question 5 .
Write the fraction that represents the dots In the triangle.

Solution:

Total number of dots $=24$
Number of dots in the triangle $=6$
$\therefore$ Fraction represents the dots in the triangle $=\frac{6}{24}$
 

Question $6 .$
Find the fractions of the shaded and unshaded portions in the following.

Solution:
(a) Total number of equal parts $=8$
Shaded parts $=2$
$\therefore$ Fraction representing shaded parts $=\frac{2}{8}$
(b) Total number of equal parts $=8$
Unshaded parts $=6$
$\therefore$ Fraction of unshaded portion $=\frac{6}{8}$

(Try These Textbook Page No. 4)
Question 1 .
Find the unknown in the following equivalent fractions.
$\begin{array}{lll}\text { i) } \frac{3}{5}=\frac{9}{\square} & \text { ii) } \frac{\square}{7}=\frac{16}{78} & \text { iii) } \frac{\square}{3}=\frac{10}{15} & \text { iv) } \frac{42}{48}=\frac{\square}{8}\end{array}$
Solution:

(Try These Textbook Page No. 7)
Question 1 .
Shade the rectangle for the given pair of fractions and say which is greater among them.

Solution:

Question 2 .
Which is greater $\frac{3}{8}$ or $\frac{3}{5}$ ?
Solution:
LCM of the denominators 8 and 5 is 40 .
Finding the equivalent fractions.
$\begin{aligned}
&\frac{3}{8}=\frac{3 \times 5}{8 \times 5}=\frac{15}{40} \\
&\frac{3}{5}=\frac{3 \times 8}{5 \times 8}=\frac{24}{40}
\end{aligned}$
Here $\frac{24}{40}>\frac{15}{40} \quad \therefore \frac{3}{5}>\frac{3}{8}$

Question $3 .$
Arrange the fractions in ascending order : $\frac{3}{5}, \frac{9}{10}, \frac{11}{15}$
Solution:
Equivalent fractions of $\frac{3}{5}$ are $\frac{6}{10}, \frac{9}{15}, \frac{12}{20}, \frac{15}{25}, \frac{18}{30}, \ldots \ldots$
Equivalent fractions of $\frac{9}{10}$ are $\frac{18}{20}, \frac{27}{30}, \ldots . .$
Equivalent fractions of $\frac{11}{15}$ are $\frac{22}{30}, \ldots . \quad$ Therefore $\frac{18}{30}<\frac{22}{30}<\frac{27}{30}$ The ascending order of given fractions is $\frac{3}{5}<\frac{11}{15}<\frac{9}{10}$

Question $4 .$
Arrange the fractions in descending order : $\frac{9}{20}, \frac{3}{4}, \frac{7}{12}$
Solution:
Equivalent fractions of $\frac{9}{20}$ are $\frac{18}{40}, \frac{27}{60}, \ldots . .$
Equivalent fractions of $\frac{3}{4}$ are $\frac{6}{8}, \frac{9}{12}, \frac{12}{16}, \frac{15}{20}, \frac{18}{24}, \frac{21}{28}, \frac{24}{32}, \frac{27}{36}, \frac{30}{40}, \frac{33}{44}, \frac{36}{48}, \frac{39}{52}, \frac{42}{56}, \frac{45}{60}, \ldots \ldots$
Equivalent fractions of $\frac{7}{12}$ are $\frac{14}{24}, \frac{21}{36}, \frac{28}{48}, \frac{35}{60}, \ldots . .$
Therefore $\frac{45}{60}>\frac{35}{60}>\frac{27}{60} .$ The descending order of given fractions is $\frac{3}{4}>\frac{7}{12}>\frac{9}{20}$