Additional Questions - Chapter 1 Fractions Term 3 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

Updated By SaraNextGen

On April 24, 2024, 11:35 AM

Additional Questions
Question $1 .$
Color the part according to the given fraction.

Solution:
(i) Here $\frac{3}{4}$ shows out of 4 parts 3 parts are shaded

(ii) Here $\frac{2}{4}$ shows out of 4 parts 2 parts are shaded

Question $2 .$
Identify the error if any

Solution:
In the given figure, shaded portion is not equal to unshaded portion. So the fraction is not equal to $\frac{1}{2}$.
 

Question $3 .$
What fraction of an hour is 20 minutes?
Solution:
We know that total minutes in an hour $=60 \mathrm{~min}$
$\therefore$ Required fraction $=\frac{20 \mathrm{~min}}{60 \mathrm{~min}}=\frac{20}{60}=\frac{1}{3}$

Question $4 .$
Write a fraction equivalent to $\frac{3}{5}$ with numerator 15 .
Solution:
Given, numerator of an equivalent fraction $=15$
Equivalent fraction of $\frac{3}{5}=\frac{3 \times 5}{5 \times 5}=\frac{15}{25}$
 

Question $5 .$
Which is the larger fraction $\frac{6}{10}$ or $\frac{7}{10} ?$
Solution:
Here the denominators, of both fractions are same.
Also $7>6$ So $\frac{7}{10}>\frac{6}{10}$

Question $6 .$
Sona got one-fifth of the total marks and Mala got one-third of the total marks. Who got more?
Solution:
We know that if the numerators are same in two fractions, the fraction with smaller denominator is greater.
$\therefore \frac{1}{3}>\frac{1}{5}$
$\therefore$ Mala got more marks.
 

Question $7 .$
A piece of rope $\frac{7}{8}$ metre long is cut into two pieces. One piece was $\frac{1}{4} \mathrm{~m}$ long. How long is the other?

Solution:
Total length of the rope $=\frac{7}{8} \mathrm{~m}$
Length of one piece $=\frac{1}{4} \mathrm{~m}$
$\therefore$ Length of other piece $=\left(\frac{7}{8}-\frac{1}{4}\right) \mathrm{m}=\frac{7-2}{8} \mathrm{~m}=\frac{5}{8} \mathrm{~m}$

Question $8 .$
Meena travelled $3 \frac{1}{2} \mathrm{~km}$ by bus, then she walked $1 \frac{1}{8} \mathrm{~km}$ to reach a town. How much she travelled to reach-the town?
Solution:

Distance travelled by bus $=3 \frac{\mathrm{I}}{2} \mathrm{~km}$
Distance travelled by walk $=1 \frac{1}{8} \mathrm{~km}$
$\therefore$ Total distance travelled $=\left(3 \frac{1}{2}+1 \frac{1}{8}\right) \mathrm{km}=\left(\frac{7}{2}+\frac{9}{8}\right)$
$=\left(\frac{28}{8}+\frac{9}{8}\right)=\frac{28+9}{8} \mathrm{~km}=\frac{37}{8} \mathrm{~km}$=4 \frac{5}{8}
She travelled $4 \frac{5}{8} \mathrm{~km}$

Question $9 .$
What should be subtracted from the sum of $2 \frac{1}{4}$ and $3 \frac{1}{7}$ to get $2 \frac{3}{28} ?$

Solution:
Sum of $2 \frac{1}{4}$ and $3 \frac{1}{7}=2 \frac{1}{4}+3 \frac{1}{7}$
$\begin{aligned}
&=2+\frac{1}{4}+3+\frac{1}{7}=(2+3)+\left(\frac{1}{4}+\frac{1}{7}\right) \\
&=5+\frac{(1 \times 7)+(1 \times 4)}{28}=5+\frac{11}{28}=5 \frac{11}{28}
\end{aligned}$
Now $5 \frac{11}{28}-$ A number $=2 \frac{3}{28}$$
\begin{aligned}
\therefore \text { Required number } &=5 \frac{11}{28}-2 \frac{3}{28}=5+\frac{11}{28}-\left(2+\frac{3}{28}\right)=(5-2)+\left(\frac{11}{28}-\frac{3}{28}\right) \\
&=3+\left(\frac{11-3}{28}\right)=3+\frac{8}{28}=3+\frac{2}{7}=3 \frac{2}{7}
\end{aligned}$

Question $10 .$
Compare $4 \frac{2}{3}$ and $5 \frac{3}{7}$ ?
Solution:
$\begin{aligned}
&4 \frac{2}{3}=\frac{14}{3}=\frac{14 \times 7}{3 \times 7}=\frac{98}{21} \\
&5 \frac{3}{7}=\frac{38}{7}=\frac{38 \times 3}{7 \times 3}=\frac{114}{21} \\
&\frac{114}{21}>\frac{98}{21} \Rightarrow 5 \frac{3}{7}>4 \frac{2}{3}
\end{aligned}$