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Exercise 7.4 - Chapter 7 Permutations & Combinations class 11 ncert solutions Maths - SaraNextGen [2024-2025]


Updated By SaraNextGen
On April 24, 2024, 11:35 AM

Question 1:

Ifhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5557/Chapter%207_html_680771a9.gif, findhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5557/Chapter%207_html_m1974bb91.gif.

Answer:

It is known that,https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5557/Chapter%207_html_m7207bbe5.gif

Therefore,

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5557/Chapter%207_html_m5594c505.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5557/Chapter%207_html_m6348a58e.gif

Question 2:

Determine n if

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5558/Chapter%207_html_2bfd765e.gif (ii) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5558/Chapter%207_html_m7f21859f.gif

Answer:

(i)

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5558/Chapter%207_html_5112b759.gif

(ii)

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5558/Chapter%207_html_m1a797658.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5558/Chapter%207_html_238cfa84.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5558/Chapter%207_html_2d649dc.gif

Question 3:

How many chords can be drawn through 21 points on a circle?

Answer:

For drawing one chord on a circle, only 2 points are required.

To know the number of chords that can be drawn through the given 21 points on a circle, the number of combinations have to be counted.

Therefore, there will be as many chords as there are combinations of 21 points taken 2 at a time.

Thus, required number of chords =https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/4227/chapter%207_html_m559d4c03.gif

Question 4:

In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

Answer:

A team of 3 boys and 3 girls is to be selected from 5 boys and 4 girls.

3 boys can be selected from 5 boys in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5559/Chapter%207_html_m4fd60ef3.gifways.

3 girls can be selected from 4 girls in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5559/Chapter%207_html_2e2a392b.gifways.

Therefore, by multiplication principle, number of ways in which a team of 3 boys and 3 girls can be selected https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5559/Chapter%207_html_4fb2c9c9.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5559/Chapter%207_html_429cf5a.gif

Question 5:

Find the number of ways of selecting 9 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 3 balls of each colour.

Answer:

There are a total of 6 red balls, 5 white balls, and 5 blue balls.

9 balls have to be selected in such a way that each selection consists of 3 balls of each colour.

Here,

3 balls can be selected from 6 red balls in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5658/Ch-7_html_6c68f037.gifways.

3 balls can be selected from 5 white balls in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5658/Ch-7_html_m4fd60ef3.gifways.

3 balls can be selected from 5 blue balls in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5658/Ch-7_html_m4fd60ef3.gif ways.

Thus, by multiplication principle, required number of ways of selecting 9 balls

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5658/Ch-7_html_m12894072.gif

Question 6:

Determine the number of 5 card combinations out of a deck of 52 cards if there is exactly one ace in each combination.

Answer:

In a deck of 52 cards, there are 4 aces. A combination of 5 cards have to be made in which there is exactly one ace.

Then, one ace can be selected in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5561/Chapter%207_html_m49b3dcb5.gifways and the remaining 4 cards can be selected out of the 48 cards in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5561/Chapter%207_html_m7adbb88d.gifways.

Thus, by multiplication principle, required number of 5 card combinations https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5561/Chapter%207_html_m3c5cfb5e.gif

Question 7:

In how many ways can one select a cricket team of eleven from 17 players in which only 5 players can bowl if each cricket team of 11 must include exactly 4 bowlers?

Answer:

Out of 17 players, 5 players are bowlers.

A cricket team of 11 players is to be selected in such a way that there are exactly 4 bowlers.

4 bowlers can be selected in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5562/Chapter%207_html_m40103821.gifways and the remaining 7 players can be selected out of the 12 players inhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5562/Chapter%207_html_20ec8583.gif ways.

Thus, by multiplication principle, required number of ways of selecting cricket team https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5562/Chapter%207_html_m72a3fbba.gif

Question 8:

A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.

Answer:

There are 5 black and 6 red balls in the bag.

2 black balls can be selected out of 5 black balls in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5563/Chapter%207_html_m4147acd7.gifways and 3 red balls can be selected out of 6 red balls in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5563/Chapter%207_html_6c68f037.gif ways.

Thus, by multiplication principle, required number of ways of selecting 2 black and 3 red balls https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5563/Chapter%207_html_1f114cce.gifhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5563/Chapter%207_html_m1b7e4b87.gif

Question 9:

In how many ways can a student choose a programme of 5 courses if 9 courses are available and 2 specific courses are compulsory for every student?

Answer:

There are 9 courses available out of which, 2 specific courses are compulsory for every student.

Therefore, every student has to choose 3 courses out of the remaining 7 courses. This can be chosen in https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5564/Chapter%207_html_m56c5ec0.gif ways.

Thus, required number of ways of choosing the programme

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/167/5564/Chapter%207_html_m37c020e0.gif

Also Read : Miscellaneous-Exercise-Chapter-7-Permutations-&-Combinations-class-11-ncert-solutions-Maths

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