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In Text Questions (Text Book Page No. 51,53,54,57,61,64,68) - Chapter 2 Measurements 8th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]


Updated By SaraNextGen
On April 24, 2024, 11:35 AM

Think (Text Book Page No. 51)
Question $1 .$

$\frac{22}{7}$ and $3.14$ are rational numbers. Is ' $\pi$ ' a rational number? Why?
Answer:
$\frac{22}{7}$ and $3.14$ are rational numbers $\pi$ has non-terminating and non-repoating decimal expansion. So it is not a rational number. it is an irrational number.
 

Question $2 .$
When is the' $\pi$ 'day celebrated? Why?
Answer:
March $14^{\text {th }}$ i.e. $3 / 14$ every year. Approximately value of' ' $\pi$ ' is $3.14$.

 

Think (Text Book Page No. 53)
The given circular figure is did into six equal parts. Can we call the parts as sectors? Why?

Answer:
No, the equal parts are not sectors. Because a sector is a plane surface that is enclosed between two radii and the circular arc of the circle. Here the boundaries are not radii.


Try These (Text Book Page No. 53)
Fill the central angle of the shaded sector (each circle is divided into equal sectors)

 

Think (Text Book Page No. 54)
Question 1.

Instead of multiplying by $\frac{1}{2}, \frac{1}{3}$ and $\frac{1}{4}$, we shall multiply by $\frac{180^{\circ}}{360^{\circ}}, \frac{120^{\circ}}{360^{\circ}}$ and $\frac{90^{\circ}}{360^{\circ}}$ respectively. why?
Answer:
So, $\frac{180^{\circ}}{360^{\circ}}=$ $\frac{120^{\circ}}{360^{\circ}}=\frac{1}{3}$ $\frac{90^{\circ}}{360^{\circ}}=\frac{1}{4}$
 

Think (Text Book Page No. 57)
If the radius of a circle is doubled, what will happen to the area of the new circle so formed?
Answer:
If $\mathrm{r}=2 \mathrm{r}_{1} \Rightarrow$ Area of the circle $=\pi \mathrm{r}^{2}=\pi\left(2 \mathrm{r}_{1}\right)^{2}=\pi 4 \mathrm{r}_{1}^{2}$
Area $=4 \times$ old area


Think (Text Book Page No. 61)
All the sides of a rhombus are equal. It is a regular polygon?
Answer:
For a regular polygon all sides and all the angles must be equal. But in a rhombus all the sides are equal.
But all the angles are not equal
$\therefore$ It is not a regular polygon.

 

Try This (Text Ronk Page Nn. 64)
In the above example split the given mat into two trapeziums and verify your answer.
Answer:
Area of the mat = Area of I trapezium + Area of II trapezium
$=\left[\frac{1}{2} \times \mathrm{h}_{1} \times\left(\mathrm{a}_{1}+\mathrm{b}_{1}\right)\right]+\left[\frac{1}{2} \times \mathrm{h}_{2} \times\left(\mathrm{a}_{2}+\mathrm{b}_{2}\right)\right]$ sq. units
$=\left[\frac{1}{2} \times 2 \times(7+5)\right]+\frac{1}{2} \times 2 \times(9+7)$ sq.feet
$=12+16=28$ sq.feet
$\therefore$ Cost per sq.feet $=220$
Cost for 28 sq. feet $=₹ 20 \times 28=₹ 560$
$\therefore$ Total cost for the entire mat $=₹ 560$
Both the answers are the same.


Try This (Text Book Page No. 68)
Tabulate the number of faces (F), vertices (V) and edges (E) for the following polyhedrons. Also find $F$ $+V-E$

What do you observe from the above table? We observe that, $F+V-E=2$ in all the cases. This is true for any polyhedron and this relation $\mathrm{F}+\mathrm{V}-\mathrm{E}=2$ is known as Euler's formula.
Answer:

Also Read : In-Text-Questions-(Text-Book-Page-No.-74,-75,77,78,79,81,83,84,86,87,88,91,94)-Chapter-3-Algebra-8th-Maths-Guide-Samacheer-Kalvi-Solutions

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