A bullet of mass 0.01 kg and travelling at a speed of 500 m/s strikes a block of 2 kg which is suspended by a string of length 5m. The centre of gravity of the block is found to rise a vertical distance of 0.1m. What is the speed of the bullet after it emerges from the block? |
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a) |
200 m/s |
b) |
220 m/s |
c) |
204 m/s |
d) |
284 m/s |
A bullet of mass 0.01 kg and travelling at a speed of 500 m/s strikes a block of 2 kg which is suspended by a string of length 5m. The centre of gravity of the block is found to rise a vertical distance of 0.1m. What is the speed of the bullet after it emerges from the block? |
|||||||
a) |
200 m/s |
b) |
220 m/s |
c) |
204 m/s |
d) |
284 m/s |
(b) Suppose the velocity of the bullet of mass Applying law of conservation of linear momentum, we get Or 500 Or 5 = 2 Now, the kinetic energy gained by the block Or Putting the value of
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A disc of radius rolls on a horizontal ground with linear acceleration
and angular acceleration
as shown in Figure. The magnitude of acceleration of point
asshown in the figure at an instant when its linear velocity is
and angular velocity is
will be
a) |
|
b) |
|
c) |
|
d) |
|
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