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A wooden block of mass 10 g is dropped from the top of a tower 100 m high. Simultaneously, a bullet of mass 10 g is fired from the foot of the tower vertically upwards with a velocity of 100 m/s. If the bullet is embedded in it, how high will the block rise above the top of tower before it starts falling? )

a)

75 m

b)

85 m

c)

80 m

d)

10 m


Question ID - 100305 | SaraNextGen Answer

A wooden block of mass 10 g is dropped from the top of a tower 100 m high. Simultaneously, a bullet of mass 10 g is fired from the foot of the tower vertically upwards with a velocity of 100 m/s. If the bullet is embedded in it, how high will the block rise above the top of tower before it starts falling? )

a)

75 m

b)

85 m

c)

80 m

d)

10 m

1 Answer - 5876 Votes

3537

Answer Key : (a) -

(a)

The bullet and block will meet after time

During this time, distance travelled by the block,

Distance travelled by the bullet,

m

Velocity of the bullet before collision,

 m/s

Velocity of the block before collision,

  m/s

Let be the combined velocity after collision

According to the law of conservation of momentum,

or 

(Velocity in upward direction is considered positive)

Solving, we get  m/s

Maximum height risen by the block m

Height reached above the top of the tower is

 m



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