Two blocks and each of mass , are connected by a massless spring of natural length and spring constant . The blocks are initially resting on a smooth horizontal floor with the spring at its natural length, as shown in Fig. A third identical block , also of mass , moves on the floor with a speed along the line joining and and collides elastically with Then
a) |
The kinetic energy of the system, at maximum compression of the spring, is zero |
b) |
The kinetic energy of the system, at maximum compression of the spring, is |
c) |
The maximum compression of the spring is |
d) |
The maximum compression of the spring is |
Two blocks and each of mass , are connected by a massless spring of natural length and spring constant . The blocks are initially resting on a smooth horizontal floor with the spring at its natural length, as shown in Fig. A third identical block , also of mass , moves on the floor with a speed along the line joining and and collides elastically with Then
a) |
The kinetic energy of the system, at maximum compression of the spring, is zero |
b) |
The kinetic energy of the system, at maximum compression of the spring, is |
c) |
The maximum compression of the spring is |
d) |
The maximum compression of the spring is |
(b,d)
In situation (i), mass is moving towards right with velocity . and are at rest. In situation (ii), which is just after the collision of with , stops and acquires a velocity When starts moving towards right, the spring suffers a compression due to which also starts moving towards right. The compression of the spring continues till there is a relative velocity between and . Once this relative velocity becomes zero, both and move with the same velocity and the spring is in a state of maximum compression
Applying momentum conservation in situations (ii) and (iii),
Therefore, KE of the system in situation (iii) is
Applying energy conservation, we get
Solve to get