Two identical buggies each of mass 150 kg move one after the other without friction with same velocity 4 m/s. A man of mass 
rides the rear buggy. At a certain moment, the man jumps into the front buggy with a velocity 
relative to his buggy. As a result of this process, rear buggy stops. If the sum of kinetic energies of the man and the front buggy just after collision with the front buggy differs from that just before collision by 2700 J, then
The mass 
of the man is
a)
60 kg
b)
75 kg
c)
50 kg
d)
90 kg
rides the rear buggy. At a certain moment, the man jumps into the front buggy with a velocity relative to his buggy. As a result of this process, rear buggy stops. If the sum of kinetic energies of the man and the front buggy just after collision with the front buggy differs from that just before collision by 2700 J, thenThe mass of the man is
a)
60 kg
b)
75 kg
c)
50 kg
d)
90 kg
Question ID - 101256 | SaraNextGen Top Answer Two identical buggies each of mass 150 kg move one after the other without friction with same velocity 4 m/s. A man of mass rides the rear buggy. At a certain moment, the man jumps into the front buggy with a velocity relative to his buggy. As a result of this process, rear buggy stops. If the sum of kinetic energies of the man and the front buggy just after collision with the front buggy differs from that just before collision by 2700 J, then
The mass of the man is
a)
60 kg
b)
75 kg
c)
50 kg
d)
90 kg
Two identical buggies each of mass 150 kg move one after the other without friction with same velocity 4 m/s. A man of mass rides the rear buggy. At a certain moment, the man jumps into the front buggy with a velocity relative to his buggy. As a result of this process, rear buggy stops. If the sum of kinetic energies of the man and the front buggy just after collision with the front buggy differs from that just before collision by 2700 J, then
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The mass |
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|
a) |
60 kg |
b) |
75 kg |
c) |
50 kg |
d) |
90 kg |
|
(c) Since rear buggy stops and velocity of man relative to this buggy is
Kinetic energy of man and front buggy (just before collision)is
Let velocity of the front buggy, after collision, be Applying law of conservation of momentum on the system of front buggy and man, we get
Kinetic energy of the system after collision is
But From above three equations,
|
, therefore, absolute velocity of man at the time of jump is 
. Applying law of conservation of momentum on the system of rear buggy and man
(i)
(ii)
(iii)
