In the arrangement shown in Fig., the ball and the block have the same mass 1 kg each,
and length
m. Coefficient of friction between the block and the floor is 0.5. When the ball is released from the position shown in Fig., it collides with the block and the block stops after moving a distance 2.50 m
The velocity of block just after collision is |
|||||||
a) |
10 m/s |
b) |
5 m/s |
c) |
2.5 m/s |
d) |
3 m/s |
In the arrangement shown in Fig., the ball and the block have the same mass 1 kg each,
and length
m. Coefficient of friction between the block and the floor is 0.5. When the ball is released from the position shown in Fig., it collides with the block and the block stops after moving a distance 2.50 m
The velocity of block just after collision is |
|||||||
a) |
10 m/s |
b) |
5 m/s |
c) |
2.5 m/s |
d) |
3 m/s |
(b) When ball is released, it moves along a vertical circle with centre at After collision, the block starts to move towards right. But it is retarded by force of friction and ultimately it comes to rest. According to law of conservation of energy, Kinetic energy of the block just after collision = Work done by it against friction Therefore, its velocity Where Coefficient of restitution, Where
Applying law of conservation of momentum,
Substituting in Eq. (i), we get |
First two terms are connected by some relationship. The same relationship is applicable for the next term in which one is blank space. Identify the suitable term.
Earth : Moon :: Sun : __________ |
|||||||
(a) |
Star |
(b) |
Earth |
(c) |
Sky |
(d) |
Moon |
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