In the Wheatstone’s network given, P=10
, R=15
, S=30
, the current passing through the battery (of negligible internal resistance) is
.png)
a)
0.36A
b)
Zero
c)
0.18A
d)
0.72A
, R=15 , S=30 , the current passing through the battery (of negligible internal resistance) isa)
0.36A
b)
Zero
c)
0.18A
d)
0.72A
Question ID - 151609 | SaraNextGen Top Answer In the Wheatstone’s network given, P=10 , R=15 , S=30 , the current passing through the battery (of negligible internal resistance) is
a)
0.36A
b)
Zero
c)
0.18A
d)
0.72A
In the Wheatstone’s network given, P=10 , R=15 , S=30 , the current passing through the battery (of negligible internal resistance) is
|
a) |
0.36A |
b) |
Zero |
c) |
0.18A |
d) |
0.72A |
1 Answer
127 votes
Answer Key / Explanation : (a) -
|
(a) The balanced condition for Wheatstone bridge is
as is obvious from the given values. No, current flows through galvanometer is zero. Now, P and R are in series, so Resistance
Similarly, Q and S are in series, so Resistance Net resistance of the network as
Hence,
|
and 
are in parallel.
127 votes
Answer Link
127