Three blocks A, B and C are lying on a smooth horizontal surface, as shown in the figure. A and B have equal masses, m while C has mass M. Block A is given an brutal speed v towards B due to which it collides with B perfectly inelastically. The combined mass collides with C, also perfectly in elasticity of the initial kinetic energy is lost in whole process. What is value of M/m?
Three blocks A, B and C are lying on a smooth horizontal surface, as shown in the figure. A and B have equal masses, m while C has mass M. Block A is given an brutal speed v towards B due to which it collides with B perfectly inelastically. The combined mass collides with C, also perfectly in elasticity of the initial kinetic energy is lost in whole process. What is value of M/m?
=ki m
From linear momentum conservation
Mv0=(2m+M) vf
vf=
=6
= 4