In a communication system operating at wavelength 800mm, only one percent of source frequency is available as signal bandwidth. The number of channels accommodated for transmitting TV signals of band width 6 MHz are (Take velocity of light c=3× 108m/s,h = 6.6 × 10−34 J s)
a. |
3.75×106 |
b. |
4.87×105 |
c. |
3.86×106 |
d. |
6.25×105 |
In a communication system operating at wavelength 800mm, only one percent of source frequency is available as signal bandwidth. The number of channels accommodated for transmitting TV signals of band width 6 MHz are (Take velocity of light c=3× 108m/s,h = 6.6 × 10−34 J s)
a. |
3.75×106 |
b. |
4.87×105 |
c. |
3.86×106 |
d. |
6.25×105 |
f=
= 3.75 × 1014 Hz
1 % of f = 0.0375 × 1014 Hz
=3.75 × 1012 Hz = 3.75 × 106MHz
Number of channels = = 6.25× 105
∴ Correct answer is (d)
What will be the ratio between the area of a rectangle and the area of a triangle with one of the sides of the rectangle as base and a vertex on the opposite side of the rectangle? |
|||||||
(a) |
1:2 |
(b) |
2:1 |
(c) |
3:1 |
(d) |
Data inadequate |
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