The dimensions of the field shown in the given figure are AC = 150 m, AH = 120 m, AG = 80 m, AF = 50 m, EF = 30 m, GB = 50 m, HD = 20 m. The area of this field is |
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(a) |
6500 cm |
(b) |
6550 cm |
(c) |
6600 cm |
(d) |
6650 cm |

The dimensions of the field shown in the given figure are AC = 150 m, AH = 120 m, AG = 80 m, AF = 50 m, EF = 30 m, GB = 50 m, HD = 20 m. The area of this field is |
|||||||

(a) |
6500 cm |
(b) |
6550 cm |
(c) |
6600 cm |
(d) |
6650 cm |

1 Answer

127 votes

Area of field = ar(AEF) + ar (AGB) + ar (BGC) + ar (DHC) + ar (trap DEFH)

= = 6550 m^{2}.

127 votes

127