A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of magnetic field of 0.5T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (Given charge of electron=1.6 10−19C)
a. |
2.0 |
b. |
1.6 |
c. |
1.6 |
d. |
9.1 |
A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of magnetic field of 0.5T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (Given charge of electron=1.6 10−19C)
a. |
2.0 |
b. |
1.6 |
c. |
1.6 |
d. |
9.1 |
mv= qBR …(i)
Path is straight line
it qE = qvB
From equation (i) & (ii)
m=
m=2.0 10−24 kg