A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of magnetic field of 0.5T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (Given charge of electron=1.6
10−19C)
a.
2.0
10−24kg
b.
1.6
10−19kg
c.
1.6
10−27kg
d.
9.1
10−31kg
10−19C)a.
2.0 10−24kg
b.
1.6 10−19kg
c.
1.6 10−27kg
d.
9.1 10−31kg
Question ID - 50187 | SaraNextGen Top Answer A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of magnetic field of 0.5T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (Given charge of electron=1.6 10−19C)
a.
2.0 10−24kg
b.
1.6 10−19kg
c.
1.6 10−27kg
d.
9.1 10−31kg
A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of magnetic field of 0.5T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (Given charge of electron=1.6 10−19C)
|
a. |
2.0 |
b. |
1.6 |
|
c. |
1.6 |
d. |
9.1 |
1 Answer
127 votes
Answer Key / Explanation : (a) -
mv= qBR …(i)
Path is straight line
it qE = qvB
From equation (i) & (ii)
m=
m=2.0
10−24 kg
127 votes
Answer Link
127