The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The reading of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is:
a.
5.755m
b.
5.725mm
c.
5.740m
d.
5.950mm
a.
5.755m
b.
5.725mm
c.
5.740m
d.
5.950mm
Question ID - 50186 | SaraNextGen Top Answer The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The reading of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is:
a.
5.755m
b.
5.725mm
c.
5.740m
d.
5.950mm
The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The reading of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is:
|
a. |
5.755m |
b. |
5.725mm |
|
c. |
5.740m |
d. |
5.950mm |
LC=
LC=0.5
10−2 mm
+Ve error = 3
0.5
10−2 mm
=1.5
10−2 mm =0.015 mm
Reading=MSR +CSR − (+ve error)
=5.5 mm + (48
0.5
10−2) − 0.015
=5.5+ 0.24 −0.015=5.725 mm