A satellite is moving with a constant speed v in circular orbit around the earth. An object of mass ‘m’ is ejected from the satellite such that it just escapes from the gravitational pull of earth. At the time of ejection, the kinetic energy of the object is :
(a)
(b)
(c)
2
(d)
A satellite is moving with a constant speed v in circular orbit around the earth. An object of mass ‘m’ is ejected from the satellite such that it just escapes from the gravitational pull of earth. At the time of ejection, the kinetic energy of the object is :
(a)
(b)
(c)
2
(d)
Question ID - 50220 | Top Ranker Answer | SaraNextGen
A satellite is moving with a constant speed v in circular orbit around the earth. An object of mass ‘m’ is ejected from the satellite such that it just escapes from the gravitational pull of earth. At the time of ejection, the kinetic energy of the object is :
(a)
(b)
(c)
2
(d)
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A satellite is moving with a constant speed v in circular orbit around the earth. An object of mass ‘m’ is ejected from the satellite such that it just escapes from the gravitational pull of earth. At the time of ejection, the kinetic energy of the object is : |
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(a) |
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(b) |
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(c) |
2 |
(d) |
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1 Answer - 5876 Votes
3537
Answer Key : (b) -
Answer LinkAt height r from center of earth. Orbital velocity
=
By energy conservation
KE of ‘m’ +
=0+0
(At infinity, PE=KE=0)
⇒KE of ‘m’=
=
m=
