A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The siring is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to :
(a)
16.6 cm
(b)
20.0 cm
(c)
10.0 cm
(d)
33.3 cm
A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The siring is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to :
(a)
16.6 cm
(b)
20.0 cm
(c)
10.0 cm
(d)
33.3 cm
Question ID - 50240 | SaraNextGen Top Answer
A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The siring is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to :
(a)
16.6 cm
(b)
20.0 cm
(c)
10.0 cm
(d)
33.3 cm
|
A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The siring is set into vibration using an external vibrator of frequency 100 Hz. The separation between successive nodes on the string is close to : |
|||
|
(a) |
16.6 cm |
(b) |
20.0 cm |
|
(c) |
10.0 cm |
(d) |
33.3 cm |
1 Answer
127 votes
Answer Key / Explanation : (b) -
Velocity of wave on string
V=
=
=40m/s
Now, wavelength of wave 
=
=
m
Separation between successive nodes,
=
m
=20 cm
127 votes
Answer Link
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