Last Updated On 01-06-2023 - By Jeesha Sara
The self-induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is :
(a)
437.5 J
(b)
637.5 J
(c)
740 J
(d)
540 J
The self-induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is :
(a)
437.5 J
(b)
637.5 J
(c)
740 J
(d)
540 J
Question ID - 50253 :-
The self-induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is :
(a)
437.5 J
(b)
637.5 J
(c)
740 J
(d)
540 J
|
The self-induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is : |
|||
|
(a) |
437.5 J |
(b) |
637.5 J |
|
(c) |
740 J |
(d) |
540 J |
=25
H
E=
×
× (252−102) =
525=437.5 JNext Question :
|
A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply if 11V is connected across it is: |
|||
|
(a) |
11×10−5 W |
(b) |
11×10−4 W |
|
(c) |
11×105 W |
(d) |
11×10−3 W |
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