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A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply if 11V is connected across it is:

(a)

11×10−5 W

(b)

11×10−4 W

(c)

11×105 W

(d)

11×10−3 W



Question ID - 50254 | SaraNextGen Top Answer

A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply if 11V is connected across it is:

(a)

11×10−5 W

(b)

11×10−4 W

(c)

11×105 W

(d)

11×10−3 W

1 Answer
127 votes
Answer Key / Explanation : (a) -

P=I2R

4.4=4×10−6R

R=1.1×106

P1 = =×106=11×105W

127 votes


127