SaraNextGen Study App [2022-23]
Last Updated On 23-10-2022 - By Sara

At some location on earth the horizontal component of earth’s magnetic field is 18×10−6 T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes 45° angle with horizontal in equilibrium. To keep this needle horizontal, the vertical force that should be applied at one of its ends is:

(a)

3.6×10−5 N

(b)

6.5×10−5 N

(c)

1.3×10−5 N

(d)

1.8×10−5 N


Question ID - 50256 :-

At some location on earth the horizontal component of earth’s magnetic field is 18×10−6 T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes 45° angle with horizontal in equilibrium. To keep this needle horizontal, the vertical force that should be applied at one of its ends is:

(a)

3.6×10−5 N

(b)

6.5×10−5 N

(c)

1.3×10−5 N

(d)

1.8×10−5 N

1 Answer
5876 Votes
3537

Answer Key : (b) -

Bsin45°=Fsin45°

F=2B



Next Question :

The modulation frequency of an AM radio station is 250 kHz, which is 10% of the carrier wave. If another AM station approaches you for license what broadcast frequency will you allot?

(a)

2750 kHz

(b)

2000 kHz

(c)

2250 kHz

(d)

2900 kHz


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