SaraNextGen Study App [2022-23]
Last Updated On 23-10-2022 - By Sara

Two stars of masses 3×1031kg each and at distance 2×1011m rotate in a plane about their common center of mass O. A meteorite passes through O moving perpendicular to the star’s rotation plane. In order to escape from the gravitational field of this star, the minimum speed that meteorite should have at O is: (Take Gravitational constant G=6.67×10−11 Nm2 Kg−2)   

(a)

1.4×105 m/s

(b)

24 ×104 m/s

(c)

3.8 ×104 m/s

(d)

2.8 ×105 m/s


Question ID - 50275 :-

Two stars of masses 3×1031kg each and at distance 2×1011m rotate in a plane about their common center of mass O. A meteorite passes through O moving perpendicular to the star’s rotation plane. In order to escape from the gravitational field of this star, the minimum speed that meteorite should have at O is: (Take Gravitational constant G=6.67×10−11 Nm2 Kg−2)   

(a)

1.4×105 m/s

(b)

24 ×104 m/s

(c)

3.8 ×104 m/s

(d)

2.8 ×105 m/s

1 Answer
5876 Votes
3537

Answer Key : (d) -

By energy conservation between 0 &.

+mV2 =0+0

(M is mass of star m is mass of meteorite)

⇒ V ==2.8×105m/s



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