# Two stars of masses 3×1031kg each and at distance 2×1011m rotate in a plane about their common center of mass O. A meteorite passes through O moving perpendicular to the star’s rotation plane. In order to escape from the gravitational field of this star, the minimum speed that meteorite should have at O is: (Take Gravitational constant G=6.67×10−11 Nm2 Kg−2)    (a) 1.4×105 m/s (b) 24 ×104 m/s (c) 3.8 ×104 m/s (d) 2.8 ×105 m/s

## Question ID - 50275 | SaraNextGen Top Answer Two stars of masses 3×1031kg each and at distance 2×1011m rotate in a plane about their common center of mass O. A meteorite passes through O moving perpendicular to the star’s rotation plane. In order to escape from the gravitational field of this star, the minimum speed that meteorite should have at O is: (Take Gravitational constant G=6.67×10−11 Nm2 Kg−2)    (a) 1.4×105 m/s (b) 24 ×104 m/s (c) 3.8 ×104 m/s (d) 2.8 ×105 m/s

Answer Key / Explanation : (d) -

By energy conservation between 0 &.

+mV2 =0+0

(M is mass of star m is mass of meteorite)

⇒ V ==2.8×105m/s