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Last Updated On 01-06-2023 - By Jeesha Sara

Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is :

(a)

10 N

(b)

12.5 N

(c)

7.5 N

(d)

5 N


Question ID - 50297 :-

Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is :

(a)

10 N

(b)

12.5 N

(c)

7.5 N

(d)

5 N

1 Answer
5876 Votes
3537

Answer Key : (b) -

y =

V===50 m/s

V==2500

⇒T=2500×5×103

=12.5 N



Next Question :

An equilateral triangle ABC is cut from a thin solid sheet of wood, (see figure) D, E and F are the mid-points of its sides as shown and G is the center of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I0. It the smaller triangle DEF is removed from ABC, the moment of inertia of the remaining figure about the same axis is I. then :

(a)

I=I0

(b)

I=I0

(c)

I=

(d)

I=I0


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