Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is :
(a)
10 N
(b)
12.5 N
(c)
7.5 N
(d)
5 N
Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is :
(a)
10 N
(b)
12.5 N
(c)
7.5 N
(d)
5 N
Question ID - 50297 | SaraNextGen Answer
Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is :
(a)
10 N
(b)
12.5 N
(c)
7.5 N
(d)
5 N
|
Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is : |
|||
|
(a) |
10 N |
(b) |
12.5 N |
|
(c) |
7.5 N |
(d) |
5 N |
1 Answer - 5876 Votes
=
=50 m/s
=2500