Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is : |
|||

(a) |
10 N |
(b) |
12.5 N |

(c) |
7.5 N |
(d) |
5 N |

Equation of travelling wave on a stretched string of linear density 5 g/m is y=0.03 sin (450 t−9x) where distance and time are measured is SI units. The tension in the string is : |
|||

(a) |
10 N |
(b) |
12.5 N |

(c) |
7.5 N |
(d) |
5 N |

1 Answer

127 votes

y =

V===50 m/s

V==2500

⇒T=2500×5×10^{−}^{3}

=12.5 N

127 votes

127