An equilateral triangle ABC is cut from a thin solid sheet of wood, (see figure) D, E and F are the mid-points of its sides as shown and G is the center of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I |
|||

(a) |
I=I |
(b) |
I=I |

(c) |
I= |
(d) |
I=I |

An equilateral triangle ABC is cut from a thin solid sheet of wood, (see figure) D, E and F are the mid-points of its sides as shown and G is the center of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I |
|||

(a) |
I=I |
(b) |
I=I |

(c) |
I= |
(d) |
I=I |

1 Answer

127 votes

Suppose M is mass and a is side of larger triangle, then and will be mass and side length of smaller triangle

≈

=

So, I=I_{0}=

127 votes

127