An equilateral triangle ABC is cut from a thin solid sheet of wood, (see figure) D, E and F are the mid-points of its sides as shown and G is the center of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I_{0}. It the smaller triangle DEF is removed from ABC, the moment of inertia of the remaining figure about the same axis is I. then :

(a)

I=I_{0}

(b)

I=I_{0}

(c)

I=

(d)

I=I_{0}

Question ID - 50298 :-

An equilateral triangle ABC is cut from a thin solid sheet of wood, (see figure) D, E and F are the mid-points of its sides as shown and G is the center of the triangle. The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane of the triangle is I_{0}. It the smaller triangle DEF is removed from ABC, the moment of inertia of the remaining figure about the same axis is I. then :

(a)

I=I_{0}

(b)

I=I_{0}

(c)

I=

(d)

I=I_{0}

1 Answer

5876 Votes

3537

Answer Key : (d) -

Suppose M is mass and a is side of larger triangle, then and will be mass and side length of smaller triangle

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