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A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :

(a)

(b)

(c)

(d)



Question ID - 50300 | SaraNextGen Top Answer

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :

(a)

(b)

(c)

(d)

1 Answer
127 votes
Answer Key / Explanation : (b) -

For adiabatic process : TV−1=constant

For diatomic process :−1 =

∴x=

127 votes


127