Last Updated On 01-06-2023 - By Jeesha Sara
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx 
constant, then x is :
(a)
(b)
(c)
(d)
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :
(a)
(b)
(c)
(d)
Question ID - 50300 :-
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :
(a)
(b)
(c)
(d)
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A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx |
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(a) |
|
(b) |
|
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(c) |
|
(d) |
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For adiabatic process : TV
−1=constant
For diatomic process :
−1 =
∴x=
Next Question :
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The gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Considering only translational and rotational modes, the total internal energy of the system is : |
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|
(a) |
12 RT |
(b) |
20 RT |
|
(c) |
15 RT |
(d) |
4 RT |
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