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A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :

(a)

(b)

(c)

(d)


Question ID - 50300 :-

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :

(a)

(b)

(c)

(d)

1 Answer
5876 Votes
3537

Answer Key : (b) -

For adiabatic process : TV−1=constant

For diatomic process :−1 =

∴x=



Next Question :

The gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Considering only translational and rotational modes, the total internal energy of the system is :

(a)

12 RT

(b)

20 RT

(c)

15 RT

(d)

4 RT


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