A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx 
constant, then x is :
(a)
(b)
(c)
(d)
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :
(a)
(b)
(c)
(d)
Question ID - 50300 | SaraNextGen Top Answer
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx constant, then x is :
(a)
(b)
(c)
(d)
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A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx |
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(a) |
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(b) |
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(c) |
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(d) |
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1 Answer
127 votes
Answer Key / Explanation : (b) -
For adiabatic process : TV
−1=constant
For diatomic process :
−1 =
∴x=
127 votes
Answer Link
127