A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by
a.
10−3 rad/s
b.
10−1 rad/s
c.
1 rad/s
d.
10−5 rad/s
a.
10−3 rad/s
b.
10−1 rad/s
c.
1 rad/s
d.
10−5 rad/s
Question ID - 50344 | SaraNextGen Top Answer A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by
a.
10−3 rad/s
b.
10−1 rad/s
c.
1 rad/s
d.
10−5 rad/s
A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by
|
a. |
10−3 rad/s |
b. |
10−1 rad/s |
|
c. |
1 rad/s |
d. |
10−5 rad/s |
Angular frequency of pendulum
= 
= 
= 
× 
[
= angular frequency of support]
= 
× 
= 10−3 rad/sec.