A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10^{−2} m. The relative change in the angular frequency of the pendulum is best given by

a. |
10 |
b. |
10 |

c. |
1 rad/s |
d. |
10 |

A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10^{−2} m. The relative change in the angular frequency of the pendulum is best given by

a. |
10 |
b. |
10 |

c. |
1 rad/s |
d. |
10 |

1 Answer

127 votes

Angular frequency of pendulum

=

=

= ×

[ = angular frequency of support]

= ×

= 10^{−3 } rad/sec.

127 votes

127