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Last Updated On 01-06-2023 - By Jeesha Sara

A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by

a.

10−3 rad/s

b.

10−1 rad/s

c.

1 rad/s

d.

10−5 rad/s


Question ID - 50344 :-

A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by

a.

10−3 rad/s

b.

10−1 rad/s

c.

1 rad/s

d.

10−5 rad/s

1 Answer
5876 Votes
3537

Answer Key : (a) -

Angular  frequency of pendulum

 =

  =  

 =   ×

[ = angular frequency of support]

 =   ×

 = 10−3   rad/sec.



Next Question :

Two rods A and B of identical dimensions are at temperature 30°C. If A is heated upto 180°C and B upto T°C, then the new lengths are the same. If the ratio of the coefficients of linear expansion of A and B is 4 : 3, then the value of T is :

a.

270C

b.

230C

c.

250

d.

200


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