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A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by

a.

10−3 rad/s

b.

10−1 rad/s

c.

1 rad/s

d.

10−5 rad/s


Question ID - 50344 | Top Ranker Answer | SaraNextGen

A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by

a.

10−3 rad/s

b.

10−1 rad/s

c.

1 rad/s

d.

10−5 rad/s

1 Answer - 5876 Votes

3537

Answer Key : (a) -

Angular  frequency of pendulum

 =

  =  

 =   ×

[ = angular frequency of support]

 =   ×

 = 10−3   rad/sec.



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