In the above circuit, C
R2 =20
H and R1=10 . Current in L-R1 path is I1 and in C-R2 path is I2. The voltage of A.C source is given by V= 200
sin (100t) volts. The phase difference between I1 and I2 is :
(a)
30°
(b)
0°
(c)
150°
(d)
60°
In the above circuit, C R2 =20 H and R1=10 . Current in L-R1 path is I1 and in C-R2 path is I2. The voltage of A.C source is given by V= 200 sin (100t) volts. The phase difference between I1 and I2 is :
(a)
30°
(b)
0°
(c)
150°
(d)
60°
Question ID - 50733 | SaraNextGen Top Answer
In the above circuit, C R2 =20 H and R1=10 . Current in L-R1 path is I1 and in C-R2 path is I2. The voltage of A.C source is given by V= 200 sin (100t) volts. The phase difference between I1 and I2 is :
(a)
30°
(b)
0°
(c)
150°
(d)
60°
|
In the above circuit, C |
|||
|
(a) |
30° |
(b) |
0° |
|
(c) |
150° |
(d) |
60° |
1 Answer
127 votes
Answer Key / Explanation : (c) -
xe=
=
=
tan
=
1 is closed to 90
For L-R circuit
xL =wL=100
=
R1=10
tan
2=
tan
2=
3
2=60
So phase difference comes out 90 + 60 = 150°.
127 votes
Answer Link
127