In the figure, given that VBB supply can vary from0 to 5.0 V, VCC = 5V, dc = 200, RB = 100 k , RC = l k and VBE=1.0 V, The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively : |
|||
(a) |
20 |
(b) |
25 |
(c) |
25 |
(d) |
20 |
In the figure, given that VBB supply can vary from0 to 5.0 V, VCC = 5V, dc = 200, RB = 100 k , RC = l k and VBE=1.0 V, The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively : |
|||
(a) |
20 |
(b) |
25 |
(c) |
25 |
(d) |
20 |
At saturation, VCE = 0
VCE = VCC − ICRC
IC = = 5×10−3A
Given
=
=
=25 A
At input side
=
=(25mA) (100k) + 1V
VBB=3.5V