Exercise 3.2 - Chapter 3 Bill Profit and Loss Term 2 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

Updated By SaraNextGen

On April 24, 2024, 11:35 AM

Miscellaneous Practice Problems
Question $1 .$
A shopkeeper buys three articles for ₹ $325, ₹ 450$ and ₹ $510 .$ He is able to sell them for ₹ 350 , ₹ 425 and $₹ 525$ respectively. Find the gain or loss to the shopkeeper on the whole.
Solution:
C.P of three articles $=325+450+510=₹ 1285$
S.P of three articles $=350+425+525=₹ 1,300$
Here S.P > C.P
Profit $=$ S.P $-$ C.P $=1,300-1285=₹ 15$
The shopkeeper gained $=₹ 15$

Question 2 .
A stationery shop owner bought a scientific calculator for Rs 750 . He had put a battery worth Rs 100 in it. He had spent Rs 50 for its outer pouch. He was able to sell it for Rs 850 . Find his profit or loss.
Solution:
$\begin{aligned}
&\mathrm{CP}=\mathrm{Rs} 750+\mathrm{Rs} 100+\mathrm{Rs} 50 \\
&=\mathrm{Rs} 900 \\
&\mathrm{SP}=\mathrm{Rs} 850 \\
&\mathrm{SP}<\mathrm{CP} \\
&\text { Loss }=\mathrm{CP}-\mathrm{SP} \\
&=\mathrm{Rs} 900-\mathrm{Rs} 850 \\
&=\mathrm{Rs} 50
\end{aligned}$

Question $3 .$
Nathan paid $₹ 800$ and bought 10 bottles of honey from a village vendor. He sold them in a city for $₹ 100$ per bottle. Find his profit or loss.
Solution:

C.P of 10 bottles of honey $=₹ 800$
C.P of 1 bottle honey $=800 / 10=₹ 80$
S.P of a bottle honey $=₹ 100$
Here S.P > C.P
Profit per bottle $=₹ 100-₹ 80=₹ 20$
Profit for 10 bottles $=20 \times 10=₹ 200$
Profit $=₹ 200$

Question $4 .$
A man bought 400 metre of cloth for Rs 60,000 and sold it at the rate of Rs 400 per metre. Find his profit or loss.
Solution:
Cost of $400 \mathrm{~m}$ of cloth $=$ Rs 60,000
$\mathrm{CP}=\mathrm{Rs} 60,000$
Selling price of $400 \mathrm{~m}$ of cloth $=400 \times$ Rs 400
$\mathrm{SP}=\mathrm{Rs} 1,60,000$
$\mathrm{SP}>\mathrm{CP}$
Profit $=S P-C P$
$=\operatorname{Rs} 1,60,000-\operatorname{Rs} 60,000$
$=$ Rs. $1,00,000$

Challenge Problems
Question $5 .$
A fruit seller bought 2 dozen bananas at $₹ 20$ a dozen and sold them at $₹ 3$ per banana. Find his gain or loss.
Solution:
Cost of one dozen banana $=₹ 20$
Cost of 2 dozen bananas $=₹ 20 \times 2=₹ 40$
C.P $=₹ 40$
S.P per banana $=₹ 3$
S.P for 2 dozen banana $=₹ 3 \times 24=₹ 72$
Here S.P > C.P
Profit $=$ S.P $-$ C.P $=72-40=32$
Profit $=₹ 32$

Question $6 .$
A store purchased pens at Rs 216 per dozen. He paid Rs 58 for conveyance and sold the pens at the discount of Rs 2 per pen and made an overall profit of Rs 50 . Find the M.P. of each pen.
Solution:
Cost of 1 dozen pens $=\mathrm{Rs} 216+\mathrm{Rs} 58$
$\mathrm{CP}=\operatorname{Rs} 274$
Discount for each pen $=\mathrm{Rs} 2$
Overall profit $=$ Rs 50
Total discount for 12 pens $=$ Rs $2 \times 12$
$=\operatorname{Rs} 24$
Selling price of 12 pens $=\mathrm{Mp}$ - Discount
$\mathrm{SP}=\mathrm{Mp}-\mathrm{Rs} 24$
Profit $=$ SP $-$ CP
Rs $50=\mathrm{Mp}-\operatorname{Rs} 24-\operatorname{Rs} 274$
$\mathrm{MP}=\operatorname{Rs} 50+\operatorname{Rs} 24+\operatorname{Rs} 274$
$=\operatorname{Rs} 348$ (1 dozen)
MP of each pen $=$ Rs $348 / 12$
$=\operatorname{Rs} 174 / 6$
$=\operatorname{Rs} 29$

Question $7 .$
A vegetable vendor buys $10 \mathrm{~kg}$ of tomatoes per day at $₹ 10$ per $\mathrm{kg}$, for the first three days of a weak. $1 \mathrm{~kg}$ of tomatoes got smashed on every day for those 3 days. For the remaining 4 days of the week, he buys $15 \mathrm{~kg}$ of tomatoes daily at $₹ 8$ per $\mathrm{kg}$. If for the entire week he sells tomatoes at $₹ 20$ per $\mathrm{kg}$, then find his profit or loss for the week.
Solution:
Total tomatoes bought for 3 days $=3 \times 10=30 \mathrm{~kg}$
Cost of $1 \mathrm{~kg}=₹ 10$
Cost of $30 \mathrm{~kg}$ tomatoes $=30 \times 10=₹ 300$
Total tomatoes bought for other 4 days $=4 \times 15=60 \mathrm{~kg}$
Cost of $1 \mathrm{~kg}=₹ 8$
Cost of $60 \mathrm{~kg}$ tomatoes $=60 \times 8=₹ 480$
Total cost of $90 \mathrm{~kg}$ tomatoes $=300+480=₹ 780$
C.P = ₹ 780
Tomatoes smashed $=3 \mathrm{~kg}$
Total $\mathrm{kg}$ of Tomatoes for sale $=90-3=87 \mathrm{~kg}$
S.P of $1 \mathrm{~kg}$ tomatoes $=₹ 20$
S.P of $87 \mathrm{~kg}$ tomatoes $=87 \times 20=₹ 1740$
Here S.P > C.P
Profit $=$ S.P $-$ C.P $=1740-780=₹ 960$
Profit $=₹ 960$
 

Question $8 .$
An electrician buys a used T.V. for Rs 12,000 and a used Fridge for Rs 11,000 . After spending Rs 1,000 on repairing the T.V. and Rs 1500 on painting the Fridge, he fixes up the M.P. of T.V. as Rs 15,000 and that of Fridge as Rs 15,500 . If he gives Rs 1000 discount on each find his profit or loss. Solution:
Total cost price of TV and Fridge $=$ Rs $12,000+$ Rs $11,000+$ Rs $1,000+$ Rs $1,500=$ Rs 25,500

Selling price of TV $=$ MP $-$ Discount $=$ Rs $15,000-$ Rs $1,000=$ Rs 14,000
Selling price of Fridge $=$ MP $-$ Discount $=$ Rs $15,500-$ Rs $1,000=$ Rs 14,500
Total Selling price of TV and Fridge $=$ Rs $14,000+$ Rs $14,500=$ Rs 28,500
SP $>$ CP
Profit $=\mathrm{SP}-\mathrm{CP}=\operatorname{Rs} 28,500-\operatorname{Rs} 25,500=\mathrm{Rs} 3,000$