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Exercise 9.3 - Chapter 9 Differential Equations class 12 ncert solutions Maths - SaraNextGen [2024-2025]


Updated By SaraNextGen
On April 24, 2024, 11:35 AM

Question 1:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7807/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m45b65fa8.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7807/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m45b65fa8.gif

Differentiating both sides of the given equation with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7807/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1a54e347.gif

Again, differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7807/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_1a87606f.gif

Hence, the required differential equation of the given curve ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7807/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_24724108.gif

Question 2:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7808/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_2f40307e.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7808/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_2f40307e.gif

Differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7808/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7802fdc6.gif

Again, differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7808/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_215ba94c.gif

Dividing equation (2) by equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7808/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m43aa41a3.gif

This is the required differential equation of the given curve.

Question 3:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_28cc9ab6.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m78cb8a4c.gif

Differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m99a1b4f.gif

Again, differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3fd4c7f2.gif

Multiplying equation (1) with (2) and then adding it to equation (2), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m758236cb.gif

Now, multiplying equation (1) with 3 and subtracting equation (2) from it, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1b991034.gif

Substituting the values of https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m47bbbdf8.gif in equation (3), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7809/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m129795fb.gif

This is the required differential equation of the given curve.

Question 4:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7810/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1e6b17cc.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7810/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7008e2d6.gif

Differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7810/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2e6d8a5b.gif

Multiplying equation (1) with 2 and then subtracting it from equation (2), we get:

y’-2y=e2x2a+2bx+b-e2x2a+2bx⇒y’-2y=be2x                                      …(3)

Differentiating both sides with respect to x, we get:

y”-2y’=2be2x                        …4Dividing equation (4) by equation (3), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7810/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_mc6d6144.gif

This is the required differential equation of the given curve.

Question 5:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7811/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_38cd523b.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7811/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6fe4f635.gif

Differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7811/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m388dd07b.gif

Again, differentiating with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7811/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_31ab3c03.gif

Adding equations (1) and (3), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7811/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7b23a7f8.gif

This is the required differential equation of the given curve.

Question 6:

Form the differential equation of the family of circles touching the y-axis at the origin.

Answer:

The centre of the circle touching the y-axis at origin lies on the x-axis.

Let (a, 0) be the centre of the circle.

Since it touches the y-axis at origin, its radius is a.

Now, the equation of the circle with centre (a, 0) and radius (a) is

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7812/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m78d856ad.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7812/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m45e68912.jpg

Differentiating equation (1) with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7812/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3ae6d8d0.gif

Now, on substituting the value of a in equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7812/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_16e6b2c6.gif

This is the required differential equation.

Question 7:

Form the differential equation of the family of parabolas having vertex at origin and axis along positive y-axis.

Answer:

The equation of the parabola having the vertex at origin and the axis along the positive y-axis is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7813/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_34067d1c.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7813/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3482ba8a.jpg

Differentiating equation (1) with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7813/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_7854845e.gif

Dividing equation (2) by equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7813/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2d1b93ad.gif

This is the required differential equation.

Question 8:

Form the differential equation of the family of ellipses having foci on y-axis and centre at origin.

Answer:

The equation of the family of ellipses having foci on the y-axis and the centre at origin is as follows:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7814/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_5abb36a5.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7814/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m4127dc6e.jpg

Differentiating equation (1) with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7814/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_133b9d3.gif

Again, differentiating with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7814/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2139adb.gif

Substituting this value in equation (2), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7814/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m41b5b7b8.gif

This is the required differential equation.

Question 9:

Form the differential equation of the family of hyperbolas having foci on x-axis and centre at origin.

Answer:

The equation of the family of hyperbolas with the centre at origin and foci along the x-axis is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7815/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_75582719.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7815/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_5a7d2a02.jpg

Differentiating both sides of equation (1) with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7815/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_d797667.gif

Again, differentiating both sides with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7815/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m22ae9735.gif

Substituting the value ofhttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7815/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_6cff76ee.gif in equation (2), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7815/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m50fb1b86.gif

This is the required differential equation.

Question 10:

Form the differential equation of the family of circles having centre on y-axis and radius 3 units.

Answer:

Let the centre of the circle on y-axis be (0, b).

The differential equation of the family of circles with centre at (0, b) and radius 3 is as follows:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7816/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_2f7e42bf.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7816/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1eae9f72.jpg

Differentiating equation (1) with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7816/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_2507d7bd.gif

Substituting the value of (y – b) in equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7816/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m691c354f.gif

This is the required differential equation.

Question 11:

Which of the following differential equations hashttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m61c77c02.gif as the general solution?

A. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2b67ca89.gif

B. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3179f792.gif

C. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_66739e81.gif

D. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m39cb6828.gif

Answer:

The given equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7f696c14.gif

Differentiating with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6d5220dd.gif

Again, differentiating with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7817/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_454aea12.gif

This is the required differential equation of the given equation of curve.

Hence, the correct Answer is B.

Question 12:

Which of the following differential equation hashttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m5960828c.gif as one of its particular solution?

A. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m5fb757a4.gif

B. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_574fd33b.gif

C. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m4ba12a8e.gif

D. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m48c7274a.gif

Answer:

The given equation of curve is y = x.

Differentiating with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7f7ddac8.gif

Again, differentiating with respect to x, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7af9dd40.gif

Now, on substituting the values of yhttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1b7d7217.gif  from equation (1) and (2) in each of the given alternatives, we find that only the differential equation given in alternative C is correct.

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7818/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_ma9cc9cc.gif

Hence, the correct Answer is C.

Also Read : Exercise-9.4-Chapter-9-Differential-Equations-class-12-ncert-solutions-Maths

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