Given that 
= +1.23 V;
= 2.05V
= +1.09 V
= +1.4V
The strongest oxidizing agent is
(a)
Br2
(b)
Au3+
(c)
S2
(d)
O2
Given that = +1.23 V;
= 2.05V
= +1.09 V
= +1.4V
The strongest oxidizing agent is
(a)
Br2
(b)
Au3+
(c)
S2
(d)
O2
Question ID - 52434 | SaraNextGen Top Answer
Given that = +1.23 V;
= 2.05V
= +1.09 V
= +1.4V
The strongest oxidizing agent is
(a)
Br2
(b)
Au3+
(c)
S2
(d)
O2
|
Given that
The strongest oxidizing agent is |
|||
|
(a) |
Br2 |
(b) |
Au3+ |
|
(c) |
S2 |
(d) |
O2 |
1 Answer
127 votes
Answer Key / Explanation : (c) -
More positive is the reduction potential stronger is the oxidizing agent. Reduction potential is maximum for S2O82−
127 votes
Answer Link
127