Updated By SaraNextGen
On March 26, 2024, 11:35 AM
Chapter 1 - Measurements - 9th Science Guide Samacheer Kalvi Solutions - Tamil Medium - SaraNextGen [2024-2025]
Answer:
The magnitude of light year $=9.46 \times 10<$ sup $>15\mathrm{m}$. So Inian gave a correct answer.
Question $2 .$
The main scale reading while measuring the thickness of a rubber ball using Vernier Caliper is $7 \mathrm{~cm}$ and the Vernier scale coincidence is 6 . Find the radius of the ball.
Answer:
Given: The main scale reading $=7 \mathrm{~cm}$
Vernier scale coincidence $=6$
we know that least count of vernier $=0.01 \mathrm{~cm}$
The radius of the ball $=M S R+V C \times L C$
$
\begin{aligned}
& =7 \mathrm{~cm}+6 \times 0.01 \mathrm{~cm} \\
& =7 \mathrm{~cm}+0.06 \mathrm{~cm}=7.06 \mathrm{~cm}
\end{aligned}
$
Question $3 .$
Find the thickness of a five rupee coin with the screw gauge, if the pitch scale reading is $1 \mathrm{~mm}$ and its head scale coincidence is 68 .
Answer:
Given Pitch scale reading $=1 \mathrm{~mm}$
Head scale coincidence $=68$
The thickness of a fire rupee coin $=\mathrm{PSR}+\mathrm{HSC} \times \mathrm{L} . \mathrm{C} \pm \mathrm{ZE}$
$=1 \mathrm{~mm}+68 \times 0.01 \mathrm{~mm}$
$
\begin{aligned}
& =1 \mathrm{~mm}+0.68 \mathrm{~mm} \\
& =1.68 \mathrm{~mm}
\end{aligned}
$
ACTIVITY
Question $1 .$
Using Vernier caliper find the outer diameter of your pen cap.
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Answer:
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Question $2 .$
Determine the thickness of a single sheet of your science textbook with the help of a Screw gauge.
Answer:
Pitch scale reading $=0.05 \mathrm{~mm}$ L.C. $=0.1 \mathrm{~mm}$
Head scale coincidence $=02$
The thickness of a single sheet of science text book $=\mathrm{PSR}+\mathrm{HSC} \times \mathrm{L} . \mathrm{C} .+\mathrm{ZE}$
$=0.05 \mathrm{~mm}+(02 \times 0.1)$
$=0.05 \mathrm{~mm}+0.2 \mathrm{~mm}$
$=0.07 \mathrm{~mm}$
Question $3 .$
With the resources such as paper plates, teacups, thread, and sticks available at home make a model of an ordinary balance. Using standard masses find the mass of some objects.
Answer:
.png)
.png)
Answer:
The magnitude of light year $=9.46 \times 10<$ sup $>15\mathrm{m}$. So Inian gave a correct answer.
Question $2 .$
The main scale reading while measuring the thickness of a rubber ball using Vernier Caliper is $7 \mathrm{~cm}$ and the Vernier scale coincidence is 6 . Find the radius of the ball.
Answer:
Given: The main scale reading $=7 \mathrm{~cm}$
Vernier scale coincidence $=6$
we know that least count of vernier $=0.01 \mathrm{~cm}$
The radius of the ball $=M S R+V C \times L C$
$
\begin{aligned}
& =7 \mathrm{~cm}+6 \times 0.01 \mathrm{~cm} \\
& =7 \mathrm{~cm}+0.06 \mathrm{~cm}=7.06 \mathrm{~cm}
\end{aligned}
$
Question $3 .$
Find the thickness of a five rupee coin with the screw gauge, if the pitch scale reading is $1 \mathrm{~mm}$ and its head scale coincidence is 68 .
Answer:
Given Pitch scale reading $=1 \mathrm{~mm}$
Head scale coincidence $=68$
The thickness of a fire rupee coin $=\mathrm{PSR}+\mathrm{HSC} \times \mathrm{L} . \mathrm{C} \pm \mathrm{ZE}$
$=1 \mathrm{~mm}+68 \times 0.01 \mathrm{~mm}$
$
\begin{aligned}
& =1 \mathrm{~mm}+0.68 \mathrm{~mm} \\
& =1.68 \mathrm{~mm}
\end{aligned}
$
ACTIVITY
Question $1 .$
Using Vernier caliper find the outer diameter of your pen cap.
Answer:
Question $2 .$
Determine the thickness of a single sheet of your science textbook with the help of a Screw gauge.
Answer:
Pitch scale reading $=0.05 \mathrm{~mm}$ L.C. $=0.1 \mathrm{~mm}$
Head scale coincidence $=02$
The thickness of a single sheet of science text book $=\mathrm{PSR}+\mathrm{HSC} \times \mathrm{L} . \mathrm{C} .+\mathrm{ZE}$
$=0.05 \mathrm{~mm}+(02 \times 0.1)$
$=0.05 \mathrm{~mm}+0.2 \mathrm{~mm}$
$=0.07 \mathrm{~mm}$
Question $3 .$
With the resources such as paper plates, teacups, thread, and sticks available at home make a model of an ordinary balance. Using standard masses find the mass of some objects.
Answer:
