In text Questions Try These (Text book Page No. 45, 46, 49,50) - Chapter 3 - Perimeter and Area - Term 3 - 6th Maths Guide Samacheer Kalvi Solutions

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Try These (Text book Page No. 45)
Question $1 .$
Draw the following in a graph sheet?
i) Two different rectangles whose areas are $16 \mathrm{~cm}^{2}$
Solution:

ii) A shape with perimeter $14 \mathrm{~cm}$ and area 12 square $\mathrm{cm}$.

$\begin{aligned}
\text { Perimeter } &=4+3+4+3=14 \mathrm{~cm} \\
\text { Area } &=3 \times 4=12 \mathrm{~cm}^{2}
\end{aligned}$
iii) A shape with area 36 square $\mathrm{cm}$.

Area of this square $=6 \times 6=36 \mathrm{~cm}^{2}$

iv) Form different shapes using 4 unit squares and find their perimeter and area. (Sides of the squares must fit exactly)
a) 
$\begin{aligned}
\text { Perimeter } &=2(4+1)=2 \times 5=10 \mathrm{~cm} \\
\text { Area } &=1 \times b=4 \times 1=4 \mathrm{~cm}^{2}
\end{aligned}$
b) 
$\begin{aligned}
\text { Perimeter } &=2+2+2+2=8 \mathrm{~cm} \\
\text { Area } &=2 \times 2=4 \mathrm{~cm}^{2}
\end{aligned}$

Try this (Text book Page No.46)
Question $2 .$
Can you find the area of ' $L$ ' shaped figure as the difference between two areas.
Solution:
Here Area of $\mathrm{L}$ shape $=($ Area of the rectangle $\mathrm{ABCD})$
(Area of the rectangle GFHB) $=(2 \times 3)-(2 \times 1) \mathrm{cm}^{2}$
$=6-2 \mathrm{~cm}^{2}=4 \mathrm{~cm}^{2}$
 

Try these (Text book Page No. 46)
Question $1 .$
Measure using ruler and find the perimeter of each of the following diagram

Solution:
i) Perimeter $=2.5+0.5+1+1+0.5+1+0.5+1+0.5+1.5=10 \mathrm{~cm}$

ii) Perimeter $=2.5+0.5+2.5+0.5+0.5 \mathrm{~cm}=6.5 \mathrm{~cm}$
iii) Perimeter $=0.5+1+0.5+0.5+1+1+0.5+1+1.5+0.5+1+0.5 \mathrm{~cm}=9 \mathrm{~cm}$
iv) Perimeter $=2+0.5+1.5+1.5+0.5+0.5+2+1 \mathrm{~cm}=9.5 \mathrm{~cm}$

Try These (Text book Page No. 49)
Question $1 .$
Find the approximate area of the following figures:

Solution:
i) Approximate area = Number of full squares + Number of more than half squares $+\frac{1}{2} \times$ Number of half squares $=2+3+\frac{1}{2} \times 4=5+2=7 \mathrm{~cm}^{2}$
ii) Approximate area $=$ Number of full squares $+$ Number of more than half squares $+\frac{1}{2} \times$ Number of half squares $=1+2=3 \mathrm{~cm}^{2}$

iii) Approximate area $=$ Number of full squares $+$ Number of more than half squares $+\frac{1}{2} \times$ Number of half squares $=5+4=9 \mathrm{~cm}^{2}$
iv) Approximate area $=$ Number of full squares $+$ Number of more than half squares $=4+5=9 \mathrm{~cm}^{2} \quad+\frac{1}{2} \times$ Number of half squares

Try these (Text book Page No. 50 )
Question $2 .$
Fill in the blanks.
(i) $7 \mathrm{~cm}^{2}=___\mathrm{mm}^{2}$
Hint: $1 \mathrm{~cm}^{2}=100 \mathrm{~m}$
Solution:
700
(ii) $10 \mathrm{~m}^{2}=___\mathrm{cm}^{2}$
Hint: $1 \mathrm{~m}^{2}=10000 \mathrm{~cm}^{2}$
Solution:
$1,00,000$
(iii) $3 \mathrm{~km}^{2}=$ ___$\mathrm{m}^{2}$
Hint: $1 \mathrm{~km}^{2}=1000000$
Solution:
$30,00,000$