Exercise 4.2 - Chapter 4 - Algebra - Term 3 - 5th Maths Guide Samacheer Kalvi Solutions

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Ex 4.2
Question 1.
Say whether true or false
(i) $(23+4)=(4+23)$
Hint: $27=27$
Answer:
True
(ii) $(9+4)>12$
Hint: $13>12$
Answer:
True
(iii) $(9+4)<12$
Hint: $13<12$
Answer:
False
(iv) $11>121$
Answer:
False
(v) $142<142$
Answer:
False
(vi) $112=112$
Answer:
True
(vii) $(6 \times 5)(32-2)$
Hint: $30=30$
Answer:
True

(viii) $\frac{49}{7}>7$
Hint: $\frac{49}{7}=7$
Answer:
False
(ix) $(4 \times 3)=(3 \times 4)$
Hint: $4 \times 3=12$;
$3 \times 4=12$
Answer:
True
(x) $(21+0)=21$
Answer:
True
 

Question $2 .$
Fill in the blanks with the right symbol $(<>$ or $=)$.
(i) $(54 \div 9)$ $(8-3)$
Answer:
$54 \div 9=6$
$8-3=5$ $6>5$
$(54 \div 9)>8-3$
(ii) $(6+2) \quad(4 \times 2)$
Answer:
$6+2=8$
$4 \times 2=8$
$8=8$
$(6+2)=(4 \times 2)$
(iii) $(10 \times 2)$ $(15+20)$
Answer:
$10 \times 2=20$
$15+20=35$
$20<35$
$10 \times 2<15+20$

Question 3
Fill in the blanks in the expressions with the suitable number.
(i) $(1 \times 9)=(\times 1)$
Answer:
$(1 \times 9)=(9 \times 1)$
(ii) $(6 \times 3)>(8 \times \square)$
Answer:
$6 \times 3=18$
$8 \times 2=16$
$18>16$
$6 \times 3>(8 \times 2)$
(iii) $(36 \div 6)<(\square \times 7)$
Answer:
$36 \div 6=6$
$1 \times 7=7$
$6<7$
$(36 \div 6)<1 \times 7$
(iv) $(0+2)>(7 \times$
Answer:
$(0+2)=2$
$7 \times 0=0$
$2>0$
$(0+2)>(7 \times 0)$

(v) $(42 \div 7)=(4+$
Answer:
$(42 \div 7)=6$
$4+2=6$
$(42 \div 7)=(4+2)$
(vi) $(6-\square)<(1+2)$
Answer:
$6-4=2$
$1+2=3$
$2<3$
$(6-3)<(1+2)$