Exercise 7.2 (Revised) - Chapter 8 - Comparing Quantities - Ncert Solutions class 8 - Maths
Updated On 26-08-2025 By Lithanya
You can Download the Exercise 7.2 (Revised) - Chapter 8 - Comparing Quantities - Ncert Solutions class 8 - Maths with expert answers for all chapters. Perfect for Tamil & English Medium students to revise the syllabus and score more marks in board exams. Download and share it with your friends
Share this to Friend on WhatsApp
NCERT Solutions for Class 8 Maths Chapter 7 - Comparing Quantities
Ex 7.2 Question 1.
During a sale, a shop offered a discount of $10 \%$ on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs.1450and two shirts marked at Rs. 850 each?
Answer.
Rate of discount on all items $=10 \%$
Marked Price of a pair of jeans = Rs. 1450 and Marked Price of a shirt = Rs. 850
Discount on a pair of jeans
$
=\frac{\text { Rate } \times \text { M.P. }}{100}=\frac{10 \times 1450}{100}=\text { Rs. } 145
$
$\therefore$ S.P. of a pair of jeans $=$ Rs. $1450-$ Rs. $145=$ Rs. 1305
Marked Price of two shirts $=2 \times 850=$ Rs. 1700
Discount on two shirts $=\frac{\text { Rate } \times \text { M.P. }}{100}=\frac{10 \times 1700}{100}=$ Rs. 170
$\therefore$ S.P. of two shirts $=$ Rs. $1700-$ Rs. $170=$ Rs. 1530
Therefore the customer had to pay $=1305+1530$
= Discount on a pair of jeans
$
\begin{aligned}
& =\frac{\text { Rate } \times \text { M.P. }}{100}=\frac{10 \times 1450}{100} \\
& =\text { Rs. } 145
\end{aligned}
$
$\therefore$ S.P. of a pair of jeans
$
=\text { Rs. } 1450-\text { Rs. } 145=\text { Rs.2,835 }
$
Thus, the customer will have to pay Rs.2,835
Ex 7.2 Question 2.
The price of a TV is Rs. 13,000 . The sales tax charged on it is at the rate of $12 \%$. Find the amount that Vinod will have to pay if he buys it.
Answer.
C.P. $=$ Rs. 13,000 and S.T. rate $=12 \%$
Let C.P. be Rs.100, then S.P. for purchaser
$
=100+12=\text { Rs. } 112
$
$\because$ When C.P. is Rs. 100 , then S.P. $=$ Rs. 112
$\therefore$ When C.P. is Rs.1, then S.P. $=\frac{112}{100}$
$\therefore$ When C.P. is Rs. 13,000 , then S.P.
$
=\frac{112}{100} \times 13000=\text { Rs. } 14,560
$
He will have to pay Rs. 14,560
Ex 7.2 Question 3.
Arun bought a pair of skates at a sale where the discount given was $20 \%$. If the amount he pays is Rs.1,600, find the marked price.
Answer.
S.P. $=$ Rs. 1,600 and Rate of discount $=20 \%$
Let M.P. be Rs. 100 , then S.P. for customer $=100-20=$ Rs. 80
$\because$ When S.P. is Rs. 80 , then M.P. $=$ Rs. 100
$\therefore$ When S.P. is Rs.1, then M.P. $=\frac{100}{80}$
$\therefore$ When S.P. is Rs. 1600 , then M.P.
$
=\frac{100}{80} \times 1600=\text { Rs. } 2,000
$
Thus, the marked price was Rs. 2,000
Ex 7.2 Question 4.
I purchased a hair-dryer for Rs.5,400 including 8\% VAT. Find the price before VAT was added.
Answer.
C.P. $=$ Rs.5,400 and Rate of VAT $=8 \%$
Let C.P. without VAT is Rs. 100, then price including VAT $=100+8=$ Rs. 108
$\because$ When price including VAT is Rs. 108 , then original price $=$ Rs. 100
$\therefore$ When price including VAT is Rs.1, then original price $=\frac{100}{108}$
$\therefore$ When price including VAT is Rs.5400, then original price $=\frac{100}{108} \times 5400=$ Rs. 5000
Thus, the price of Hair Dryer before the addition of VAT was Rs 5000
Ex 7.2 Question 5.
An article was purchased for Rs. 1239 including GST of $18 \%$. Find the price of the
article before GST was added?
Answer.
Given,
$
\mathrm{GST}=18 \%
$
Cost with GST included $=$ Rs. 1239
Cost without GST $=\mathrm{x}$ Rs.
$
x+(18 / 100 \times x)=1239
$
cost before GST+ GST = cost with GST
$
\begin{aligned}
& x+(9 x / 50)=1239 \\
& x=1050
\end{aligned}
$
Price before GST $=1050$ rupees
